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MrMuchimi
4 years ago
12

If we just randomly guess (without any knowledge) on each of the 4 questions, what is the expected number of questions we get co

rrect
Mathematics
1 answer:
goldfiish [28.3K]4 years ago
7 0
YOUR HAIRLINE YOUR HAIR LINE YOUR HARLINE YOUR HARLINE BOIIIII ITS FU**** UP
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You are dealt two cards successively without replacement from a standard deck of 52 playing cards. Find the probability that the
kondaur [170]

Answer:

\frac{4}{52} \times \frac{4}{51}  = \frac{16}{2652} = 0.00603 = 0.603\%

Step-by-step explanation:

There are 52 cards in a standard deck, and there are 4 suits for each card. Therefore there are 4 twos and 4 tens.

At first we have 52 cards to choose from, and we need to get 1 of the 4 twos, therefore the probability is just

\frac{4}{52}

After we've chosen a two, we need to choose one of the 4 tens. But remember that we're now choosing out of a deck of just 51 cards, since one card was removed. Therefore the probability is

\frac{4}{51}

Now to get the total probability we need to multiply the two probabilities together

\frac{4}{52} \times \frac{4}{51}  = \frac{16}{2652} = 0.00603 = 0.603\%

5 0
4 years ago
The cost of a student ticket is $7 write a equation that correctly relates the total cost
daser333 [38]
X=$7  |  1 Ticket= x  |  1 Ticket = $7
6 0
4 years ago
Let f(x)= x^4 + ax^2 +b. The graph of f has a relative minimum at (0,1) and an inflection point when x=1. The values of a and b
Delvig [45]
f(x)=x^4+ax^2+b\\f'(x)=4x^3+2ax\\f''(x)=12x^2+2a\\f''(1)=12(1)^2+2a\\12(1)=-2a\\a=-6\\\\f(x)=x^4-6x^2+b\\(1)=(0)^4-6(0)^2+b\\b=1

a=-6
b=1
8 0
4 years ago
Anyone help find this out for 20 points? <br> appreciated
shusha [124]

Answer:

Unknown weight is 11.5kg.


Step-by-step explanation:

Square weight is 4kg. 4×5 =20.

Round weight is 2.5kg. 2×4+2×2.5=13.

Left pan is 4+3×2.5=4+7.5=11.5.

6 0
3 years ago
Simplify<br><br><br>5/8 m³ + 2 - 1.4 m³ =
creativ13 [48]

Answer:

-0.775m^3 + 2

3 0
3 years ago
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