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anzhelika [568]
3 years ago
12

The vertices of △JKL are J(−3, 4), K(3, 0), and L(−5, −4). The equation of the median to J is y=0. What are the coordinates of t

he centroid of △JKL?
Mathematics
1 answer:
telo118 [61]3 years ago
3 0

Answer:j

Step-by-step explanation:

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Answer:

rounded to the nearest whole number = 166

Step-by-step explanation:

Add all of the angles together, to get 39x. In a hexagon, all the angles add up to 720. Divide 720 by 39 to get x, then multiply x by 9, as that is the largest angle to get an answer rounded to the nearest whole number of 166.

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x^2-y^2

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A city has an elevation of 465 feet. Another city has an elevation of -45 feet. Which expression can be used to find the differe
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Find value of x and y
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