Question

PLEASE HELP! Geometry Question. Im stuck on how to get the answer. Brainiest for correct answer

Answer 1

Answer:

F. $4, 4\sqrt{3}$

Step-by-step explanation:

✔️Finding length of side s using:

$cos(\theta) = \frac{adjacent}{hypotenuse}$

Where,

$cos(\theta) = cos(60) = \frac{1}{2}$

Adjacent = s

Hypotenuse = 8

Plug in the values

$\frac{1}{2} = \frac{s}{8}$

Multiply both sides by 8

$\frac{1}{2} \times 8 = \frac{s}{8} \time 8$

$\frac{8}{2} = s$

$4 = s$

s = 4

✔️Finding length of side q using:

$sin(\theta) = \frac{opposite}{hypotenuse}$

Where,

$sin(\theta) = sin(60) = \frac{\sqrt{3}}{2}$

Opposite = q

Hypotenuse = 8

Plug in the values

$\frac{\sqrt{3}}{2} = \frac{q}{8}$

Multiply both sides by 8

$\frac{\sqrt{3}}{2} \times 8 = \frac{q}{8} \times 8$

$\frac{\sqrt{3}}{1} \times 4 = q$

$4\sqrt{3} = q$

$q = 4\sqrt{3}$