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KIM [24]
3 years ago
14

Jada has a new puppy that weighs 9 pounds. The vet says that the puppy is now about 20% of its adult weight. What will be the ad

ult weight of the puppy, in pounds?
Andre also has a puppy that weighs 9 pounds. The vet says that this puppy is now at about 30% of its adult weight. What will be the adult weight of Andre's puppy, in pounds?
Mathematics
1 answer:
Mamont248 [21]3 years ago
4 0

Answer:29.7

Step-by-step explanation:

30/100

9 x 3/10

90/1 x 10/3 = 90

90 divided by 30 is 30

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I NEED HELP NOW ITS DUE TOMORROW!
beks73 [17]

Answer:

2 2/5

Step-by-step explanation:

14 divided by 5/6 is 2 2/5

3 0
3 years ago
A student takes an exam containing 1414 multiple choice questions. The probability of choosing a correct answer by knowledgeable
Readme [11.4K]

Answer:

0.0082 = 0.82% probability that he will pass

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the students guesses the correct answer, or he guesses the wrong answer. The probability of guessing the correct answer for a question is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 14, p = 0.3.

If the student makes knowledgeable guesses, what is the probability that he will pass?

He needs to guess at least 9 answers correctly. So

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{14,9}.(0.3)^{9}.(0.7)^{5} = 0.0066

P(X = 10) = C_{14,10}.(0.3)^{10}.(0.7)^{4} = 0.0014

P(X = 11) = C_{14,11}.(0.3)^{11}.(0.7)^{3} = 0.0002

P(X = 12) = C_{14,12}.(0.3)^{12}.(0.7)^{2} = 0.000024

P(X = 13) = C_{14,13}.(0.3)^{13}.(0.7)^{1} = 0.000002

P(X = 14) = C_{14,14}.(0.3)^{14}.(0.7)^{0} \cong 0

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.0066 + 0.0014 + 0.0002 + 0.000024 + 0.000002 = 0.0082

0.0082 = 0.82% probability that he will pass

6 0
3 years ago
I need to prove the following statement: a number is even if and only if its last digit is even.
Tanzania [10]
It is basically like 82 84 76 94
6 0
3 years ago
Read 2 more answers
The booster club needs to raise at least $7000 for new football uniforms
HACTEHA [7]
There is not alot information to answer the question.
6 0
3 years ago
Determine what type of model bet fits the given situation: Every day, half a bacteria population dies. A. Linear B.quadratic C.
makvit [3.9K]

Answer:

Exponential

Step-by-step explanation:

<em>Starter:</em>

According to the title:

"Every day, half a bacteria population dies."

Exponential: y = ab^x ( b > 0 , b ≠ 1)

So the answer is C.

<em>Calculations:</em>

An exponential model is of the form y = a • b^t.

If you start with population of 500 million bacteria

t = 0

so 500 million = a • b^0 = a

Since every day half the population dies then in 1 day population will be 250 million

so a = 500 million, y = 250 million and t = 1

250 million = 500 million • b^1

b = 0.5

Therefore your equation would be

y = 500 million (or whatever the pop) • 0.5^t

Where t = number of days

This could also be written in exponential form ( e = 2.73)

4 0
2 years ago
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