Cos
θ
=
√
5
3
or it could be cos
θ
=
√
5
−
3
Explanation:
Since sin
θ
is negative, it can be in the third or fourth quadrant
Drawing your right-angled triangle, place your
θ
in one of three corners. Your longest side will be 3 and the side opposite the
θ
will be -2. Finally, using Pythagoras theorem, your last side should be
√
5
Now, if your triangle was in the third quadrant, you would have
cos
θ
=
√
5
−
3
since cosine is negative in the third quadrant
But if your triangle was in the fourth quadrant, you would have
cos
θ
=
√
5
3
since cosine is positive in the fourth quadrant
Pat has 4 more cards than Frank. Hope that helps! :)
Answer:
Step-by-step explanation:
x-4=0
x=4
p(x)=cx^3-15x-68=0
p(x)=c(4)^3-15(4)-68=0
p(x)=64c-60+68=0
p(x)=64c+8=0
p(x)=64c=-8
p(x)=c=-8/64
p(x)=c=-1/8
Answer:i think its 0
Step-by-step explanation:
