Answer:
7
Step-by-step explanation:
We want to find the number 4-digit of positive integers n such that removing the thousands digit divides the number by 9.
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Let the thousands digit be 'd'. Then we want to find the integer solutions to ...
n -1000d = n/9
n -n/9 = 1000d . . . . . . add 1000d -n/9
8n = 9000d . . . . . . . . multiply by 9
n = 1125d . . . . . . . . . divide by 8
The values of d that will give a suitable 4-digit value of n are 1 through 7.
When d=8, n is 9000. Removing the 9 gives 0, not 1000.
When d=9, n is 10125, not a 4-digit number.
There are 7 4-digit numbers such that removing the thousands digit gives 1/9 of the number.
Answer:
-6.21 x 10^5
Step-by-step explanation:
The negative only comes when the numbers are in the decimal to right such as 0.1 when its on the left side it just mean positive power such as 6.0= a positive, negative power = 0.6 count how many numbers there are (6) then get the last number as the whole number and the rest are behind (-6.21) count all the numbers besides the last number (6) now that is your power so you get -6.21 x 10^5
Answer:
4
Step-by-step explanation:
8x=32
x = 4
The answer is I’m just doing this for points
Answer:
500,000 to 200,000 is a 60% decrease.
