Remove the parentheses from 3(x-8)
2 answers:
You might be interested in
<h2>Greetings!</h2><h3>Firstly, the slope is found by rearranging the formula:</h3>
<h2>Hope this helps!</h2>
3y = 4x + 39
y = +
When x is 0, y = 0(x) + , so the y intercept is
So can be rearranged to
, so the slope would be
.
<h2>Hope this helps!</h2>
A 3d cardboard box has 6 sides, each of which are rectangles. If you unfold the 3D box, and flatten it out, then you'll be left with 6 rectangles such as what you see in the attachment below. This is one way to unfold the box. This flattened drawing is the net of the 3D rectangular prism. You can think of it as wrapping paper that covers the exterior of the box. There are no gaps or overlapping portions. If you can find the area of each piece of the net, and add up those pieces, that gets you the total area of the net. This is the exactly the surface area of the box.
In the drawing below, I've marked the sides as: top, bottom, left, right, front, back. This way you can see how the 3D box unfolds and how the sides correspond to one another. Other net configurations are possible.
Answer with step-by-step explanation:
The way the question is worded, this actually shouldn't be correct. The correct answer should be .
Because the trapezoids are similar, we can find the ratio of their perimeters by actually just finding the ratio of their sides.
Why?
By definition, the corresponding sides of a polygon are in a constant proportion. The perimeter is simply the sum of all sides of the polygon. Since we're just adding the sides, the proportion will still be maintained.
Therefore, we'll just need to ratio of their corresponding sides. The only two corresponding sides that are marked are and
.
The ratio of is
.
The reason why it ideally should be and not
is because the question states
, which mentions
first, so our answer should follow this respective order. I believe you were marked right anyways because the specific order is not specified, but generally, you want to give your answer respectively by default.