Answer:
0.79
Step-by-step explanation:
Here,
Let X be the event that the flights depart on time
Let Y be the event that flights arrive on time
So,
X∩Y will denote the event that the flights departing on time also arrive on time.
Let P be the probability
P(X∩Y)=0.65
And
P(X)=0.82
We have to find P((Y│X)
We know that
P((Y│X)=P(X∩Y)/P(X) )
=0.65/0.82
=0.79
So the probability that a flight that departs on schedule also arrives on schedule is: 0.79
Answer:
skp
Step-by-step explanation:
Answer:
9,288 ÷ 43 = 216
Step-by-step explanation:
9,288 ÷ 43
First divide 9,288 by 43 we get quotiest as 216 and remainder 0
= 216
72 × 1.4666666666667 = 105.6 feet per second
Answer:
C
Step-by-step explanation:
7*7=49
