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Norma-Jean [14]
3 years ago
13

A soda company puts a different symbol on a soda cap each year. ​

Mathematics
1 answer:
Olegator [25]3 years ago
3 0

Answer:

cool

Step-by-step explanation:

You might be interested in
Please help!posted picture of question
olchik [2.2K]
Answer:
\frac{x^2 - 5}{4x + 1}, x ≠ -1/4

Explanation:
We are given that:
f (x) = 4x + 1
g(x) = x² - 5

We want to find the value of (g/f)(x). This means that we will simply divide g(x) by f(x) as follows:
( \frac{g}{f} )(x) =  \frac{g(x)}{f(x)} =  \frac{x^2 - 5}{4x + 1}

Now, we should note that any function is undefined if its denominator is equal to zero.
This means that for our current function:
4x + 1 cannot be equal to zero
4x + 1 = 0
4x = -1
x = -1/4
This means that the value of x cannot be -1/4, otherwise, our function would be undefined.

Based on the above, the last option is the correct one.

Hope this helps :)
8 0
3 years ago
Imagine that you need to compute e^0.4 but you have no calculator or other aid to enable you to compute it exactly, only paper a
labwork [276]

Answer:

0.0032

Step-by-step explanation:

We need to compute e^{0.4} by the help of third-degree Taylor polynomial that is expanded around at x = 0.

Given :

e^{0.4} < e < 3

Therefore, the Taylor's Error Bound formula is given by :

$|\text{Error}| \leq \frac{M}{(N+1)!} |x-a|^{N+1}$   , where $M=|F^{N+1}(x)|$

         $\leq \frac{3}{(3+1)!} |-0.4|^4$

         $\leq \frac{3}{24} \times (0.4)^4$

         $\leq 0.0032$

Therefore, |Error| ≤ 0.0032

4 0
3 years ago
Compare 1⁄2 with 3⁄4 using ( &lt;, &gt;, =). A. 1⁄2 = 3⁄4 B. None of the above C. 1⁄2 &lt; 3⁄4 D. 1⁄2 &gt; 3⁄4
max2010maxim [7]
1/2 is less than 3/4. So 1/2 < 3/4
3 0
3 years ago
Please help again i appreciate ypur help​
zaharov [31]

Answer:

Scatter Plot 1 : No correlation (0) -

Scatter plot 2: negative Correlation (-1)

Scatter Plot 3: Positive Correlation (+1)

8 0
3 years ago
What is the value of X as a decimal?
marishachu [46]
X is a number so when u plus a letter that's still a number
6 0
2 years ago
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