Answer:
Side of 22 and height of 11
Step-by-step explanation:
Let s be the side of the square base and h be the height of the tank. Since the tank volume is restricted to 5324 ft cubed we have the following equation:
As the thickness is already defined, we can minimize the weight by minimizing the surface area of the tank
Base area with open top 
Side area 4sh
Total surface area 
We can substitute
To find the minimum of this function, we can take the first derivative, and set it to 0
![s = \sqrt[3]{10648} = 22](https://tex.z-dn.net/?f=s%20%3D%20%5Csqrt%5B3%5D%7B10648%7D%20%3D%2022)
1- B
2- C
3- B
4- D
5- D
6- C
7- B
8- C
9- C
10- C
Hope I helped you!!
I really think that I got them all right.. PLEASE tell me if I got any wrong so that I can change them :) Its been a while since I've done this... XD
Answer: the first option is the correct answer.
Step-by-step explanation:
Triangle ABC is a right angle triangle.
From the given right angle triangle,
AB represents the hypotenuse of the right angle triangle.
With m∠A as the reference angle,
AC represents the adjacent side of the right angle triangle.
BC represents the opposite side of the right angle triangle.
To determine the tangent of angle A, we would apply the Tangent trigonometric ratio. It is expressed as
Tan θ, = opposite side/adjacent side. Therefore,
Tan A = 5/5√3 = 1/√3
Rationalizing the surd, it becomes
1/√3 × √3/√3
Tan A = √3/3
Answer:
13
Step-by-step explanation:
a = 5
b = -8
5 - -8 = 13
