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Norma-Jean [14]
3 years ago
13

A soda company puts a different symbol on a soda cap each year. ​

Mathematics
1 answer:
Olegator [25]3 years ago
3 0

Answer:

cool

Step-by-step explanation:

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As her senior project, Julie has decided to raise money for a charity by hosting a Spaghetti Dinner. In order to have the dinner
natulia [17]

Answer:

The algebraic expression is 6x = 100

3 0
3 years ago
You walk 3 mi/h for 0.75h and 2.5mi/h for 2h. what is your average speed over the total distance? ​
Andre45 [30]

Answer:

Step-by-step explanation:

Total distance = 3 + 2.5 = 5.5mi/h

Total time = 0.75h + 2hr = 2. 75 hr

Average speed = 5.5 / 2.75 = 2

3 0
3 years ago
Please help and explain I'll give u 12pts
White raven [17]

-7x² + 70x - 175

= -7(x² - 10x + 25)

= -7(x - 5)²

= -7(x + -5)²

Answer: -5

7 0
3 years ago
I need help finding the domain and range, I already know is not a function​
FromTheMoon [43]

Answer:

Domain: [-4, 4]

Range: [-3, 5]

Function? No

Step-by-step explanation:

Domain is all x-values that can be inputted in the graph that returns an output.

Range is all y-values that are outputted when <em>x</em> is inputted.

A function has to pass the Vertical Line Test.

6 0
3 years ago
Write the following expression using symbolic language.
Ad libitum [116K]

Answer:

<h3>              1)   7x - 5 </h3><h3>              2)   9y - 18 </h3><h3>              3)   0.5n + 4n </h3><h3>              4)  2(w³+23)</h3><h3> Step-by-step explanation:</h3>

1)

The product of seven and a number x:   7·x = 7x

<u>Five less than the product of seven and a number x:</u>

<h3>7x - 5 </h3>

2)

nine times a number y:  9·y = 9y

<u>The difference of nine times a number y and eighteen:</u>

<h3>9y - 18 </h3>

3)

half a number n:   0.5n

four times the number:   4·n = 4n

<u>Half a number n increased by four times the number:</u>

<h3>0.5n + 4n </h3>

4)

a number w cubed:  w³

the sum of a number w cubed and twenty-three:  w³+23

<u>Twice the sum of a number w cubed and twenty-three:</u>

<h3>2(w³+23)</h3>

5 0
3 years ago
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