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natita [175]
3 years ago
13

An unknown gas has a volume of 20L at 140K. What is its volume at STP? Be sure to show the setup and the final

Chemistry
1 answer:
kramer3 years ago
6 0

Answer:

 v₂ = 39L

Explanation:

Given parameters:

Initial volume of gas  = 20L

Initial temperature  = 140K

Unknown:

Final volume  = ?

Solution:

Since the standard temperature of any gas is 273K, the final temperature is this 273K;

 Applying Charles's law:

            \frac{v_{1} }{T_{1} } = \frac{v_{2} }{T_{2} }

v and T are volume and Temperature

           \frac{20}{140}   = \frac{v_{2} }{273}  

 

         v₂ x 140  = 20 x 273

         v₂ = 39L

         

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Kobotan [32]

Answer:

Explanation:

3: Given data:

Number of moles of strontium nitrate = 3.00×10⁻³ mol

Number of atoms = ?

Solution:

There are 9 moles of atoms in 1 mole of Sr(NO₃)₂.

In 3.00×10⁻³ moles,

9 mol × 3.00×10⁻³

27.00×10⁻³ mol

Number of atoms in 3.00×10⁻³ mol of Sr(NO₃)₂:

27.00×10⁻³ mol × 6.022×10²³ atoms / 1mol

162.59×10²⁰ atoms

4)Given data:

Mass of calcium hydroxide = 4500 Kg (4500/1000 = 4.5 g)

Number of moles = ?

Solution:

Number of moles = mass in g/molar mass

by putting values,

Number of moles = 4.5 g/ 74.1 g/mol

Number of moles = 0.06 mol

5) Given data:

Number of atoms of silver nitrate = 1.06×10²³

Number of moles = ?

Solution:

1 mole of any substance contain  6.022×10²³ atoms .

1.06×10²³ atoms × 1 mol /  6.022×10²³ atoms

0.176 moles of silver nitrate

8 0
3 years ago
Which phase change is an example of an exothermic process?
liberstina [14]

its solid to liquid


5 0
3 years ago
Given the following balanced equation, determine the rate of reaction with respect to [O2]. If the rate of formation of O2 is 7.
murzikaleks [220]

Answer: The rate of the loss of O_3 is 0.52M/s

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

2O_3(g)\rightleftharpoons 3O_2(g)

Rate of disappearance of O_3 =-\frac{1d[O_3]}{2dt}

Rate of formation of O_2 =+\frac{1d[O_2]}{3dt}

-\frac{1d[O_3]}{2dt}=+\frac{1d[O_2]}{3dt}

Rate of formation of O_2 = 7.78\times 10^{-1}M/s

Thus Rate of disappearance of O_3 =\frac{2d[O_2]}{3dt}=\frac{2}{3}\times 7.78\times 10^{-1}M/s=0.52M/s

8 0
4 years ago
If 1.0 mole of methane reacts with oxygen to produce carbon dioxide and water, what mass of water is produced?
kari74 [83]

Answer:

36 grams

Explanation:

3 0
3 years ago
If a gas is initially at a pressure of 9 atm, a volume of 21 liters, and a temperature of 253 K, and then the pressure is raised
alex41 [277]

Answer:

15.04 mL

Explanation:

Using Ideal gas equation for same mole of gas as

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

Given ,  

V₁ = 21 L

V₂ = ?

P₁ = 9 atm

P₂ = 15 atm

T₁ = 253 K

T₂ = 302 K

Using above equation as:

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

\frac {{9}\times {21}}{253}=\frac {{15}\times {V_2}}{302}

Solving for V₂ , we get:

<u>V₂ = 15.04 mL</u>

3 0
3 years ago
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