An unknown gas has a volume of 20L at 140K. What is its volume at STP? Be sure to show the setup and the final
1 answer:
Answer:
v₂ = 39L
Explanation:
Given parameters:
Initial volume of gas = 20L
Initial temperature = 140K
Unknown:
Final volume = ?
Solution:
Since the standard temperature of any gas is 273K, the final temperature is this 273K;
Applying Charles's law:
=
v and T are volume and Temperature
=
v₂ x 140 = 20 x 273
v₂ = 39L
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Answer:
Explanation:
Hello,
In this case, for the given information, we can compute the rate of disappearance of NO₂ by using the following rate relationship:
Whereas it is multiplied by the the inverse of the stoichiometric coefficient of NO₂ in the reaction that is 2. Moreover, the subscript <em>f</em> is referred to the final condition and the subscript <em>0</em> to the initial condition, thus, we obtain:
Clearly, it turns out negative since the concentration is diminishing due to its consumption.
Regards.