Answer:
legs of table +10N and -10N. fish tank +120.N - 70N. top of table +70N.
+120N. botom of fish tank -120N. and plz dont delit my anser
Explanation:
Answer:
• From avogadro's number:
Answer:
(+)-cholesterol = 71.88%
(-)-cholesterol = 28.12%
Explanation:
<em>Asuming 1 gram of sample is dissolved in 1mL of water and the sample cell was 1dm long.</em>
Enantiomeric excess is defined as the amount of pure enantiomer in a sample. The formula is:
ee = [α]mixture / [α]pure enantiomer.
Replacing:
ee = 14° / 32°×100 = 43.75%
As the sample is 14°, There is an excess of (+)-cholesterol and 56.25% is a 1:1 mixture of enantiomers.
That means percent composition of enantiomers is:
<h3>(+)-cholesterol = 43.75% + 56.25%/2 = 71.88%</h3><h3>(-)-cholesterol = 56.25%/2 = 28.12%</h3>