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vaieri [72.5K]
3 years ago
7

Which phase change is an example of an exothermic process?

Chemistry
1 answer:
liberstina [14]3 years ago
5 0

its solid to liquid


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The sum of two number is 50,and their difference is 30.find the sum​
kompoz [17]

Answer:

40 and 10

Explanation:

40 plus 10 is 50 40 minus 10 is 30

4 0
3 years ago
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Why are pennies good for simulating radioactive atoms? Check all that apply
gavmur [86]

Answer:

all of them are correct.

Explanation:

Just took it on e2020

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3 years ago
would the pressure exerted by the gas in the tank would increase if the scuba tank were to increase in temperature?
ludmilkaskok [199]

Answer:

In fact, a full scuba tank will gain about 5-6 psi for every degree of temperature increase. This is one reason that full tanks should not be left in a hot trunk of a car. A tank filled to 3000 psi could easily reach 3500 psi if the temperature of it increased substantially.

6 0
3 years ago
It takes 38.6 kJ of energy to vaporize 1.00 mol of ethanol (MW: 46.07 g/mol). What will be ΔSsys for the vaporization of 8.00 g
KIM [24]

Answer:

\Delta S_{sys}=0.020kJ=20J

Explanation:

Hello!

In this case, given the required energy to vaporize 1.00 mol of ethanol as the enthalpy of vaporization:

\Delta H_{vap}=\frac{38.6kJ}{1.00mol}=38.6kJ/mol

We can compute the entropy of the system for the vaporization of 8.00 g of ethanol, by first computing the moles:

n_{et}=8.00g*\frac{1mol}{46.07g} =0.174mol

And then setting up the following expression:

\Delta S_{sys}=\frac{n_{et}*\Delta H_{vap}}{T}

Whereas the temperature is in kelvins; thus, we obtain:

\Delta S_{sys}=\frac{0.174mol*38.6\frac{kJ}{mol} }{79.6+273.15K}\\\\\Delta S_{sys}=0.020kJ=20J

Best regards!

5 0
3 years ago
30 ml of. 150 m cacl2 is added to a 15 ml of. 100 m agno3
ycow [4]

The mass of the formed precipitate of AgCl in the reaction is 1.29 grams.

<h3>How do we find moles from molarity?</h3>

Moles (n) of any substance from molarity (M) will be calculated by using the below equation:
M = n/V, where

V = volume in L

Given chemical reaction is:
2AgNO₃(aq) + CaCl₂(aq) → 2AgCl(s) + Ca(NO₃)₂(aq)

  • Moles of CaCl₂ = 0.150M × 0.03L = 0.0045 moles
  • Moles of AgNO₃ = 0.100M × 0.015L = 0.0015 moles

From the stoichiometry of the reaction, mole ratio of AgNO₃ to CaCl₂ is 2:1.

0.0015 moles of AgNO₃ = reacts with 1/2×0.0045 = 0.00075 moles of CaCl₂

Here CaCl₂ is the limiting reagent, and formation of precipitate depends on this only.

Again from the stoichiometry of the reaction:

0.0045 moles of CaCl₂ = produces 2(0.0045) = 0.009 moles of AgCl

Mass of 0.009 moles AgCl will be calculated as:

n = W/M, where

  • W = required mass
  • M = molar mass = 143.45 g/mol

W = (0.009)(143.45) = 1.29g

Hence required mass of precipitate is 1.29 grams.

To know more about moles & molarity, visit the below link:
brainly.com/question/24322641

#SPJ4

8 0
2 years ago
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