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Talja [164]
3 years ago
13

HELP ME PLZ!!! I really dont know this!!! What characteristic of metals makes them good electrical conductors? -They have mobile

protons. -They have mobile valence electrons. -Their crystal structures can be rearranged easily. -They have mobile cations.
Chemistry
1 answer:
Natasha2012 [34]3 years ago
6 0

Answer:

To have a high electrical conductivity, a normal metal should have mobile valence electrons and a long electron mean free path.

Explanation:

A long mean free path means that the electron goes a long distance between scattering events.

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INFORMATION:

We have the following statements

And we must complete them

STEP BY STEP EXPLANATION:

To complete the statements, we need to classify matter according to its state:

- Solid:

there is not enough thermal energy to overcome the intermolecular interactions between the particles. As a result, solids have a definite shape and volume.

- Liquid:

That describes the liquid state. In a liquid, the particles are still in close contact, so liquids have a definite volume. However, because the particles can move about each other rather freely, a liquid has no definite shape and takes a shape dictated by its container.

- Gas:

That describes the gas state, which we will consider in more detail elsewhere. Like liquids, gases have no definite shape, but unlike solids and liquids, gases have no definite volume either.

Finally, we know that:

- A solid has a definite volume and has a definite shape

- A liquid has a definite volume and has not a definite shape

- A gas has not a definite volume and has not a definite shape

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- A solid has a definite volume and has a definite shape

- A liquid has a definite volume and has not a definite shape

- A gas has not a definite volume and has not a definite shape

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Which of the following is a statement of Hess's law?
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How many molecules are in 3.6 grams of NaCl?
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Answer:

\boxed{\text{None}}

Explanation:

There are no molecules in NaCl, because it consists only of ions.

However, we can calculate the number of formula units (FU) of NaCl.

Step 1. Calculate the moles of NaCl

\text{No. of moles}=\text{3.6 g NaCl}\times \dfrac{\text{1 mol NaCl}}{\text{63.54 g NaCl}} = \text{0.0567 mol NaCl}

Step 2. Convert moles to formula units

\text{FU} = \text{0.0567 mol NaCl} \times \dfrac{6.022 \times 10^{23}\text{ FU NaCl}}{\text{1 mol NaCl}}\\\\= 3.4 \times 10^{22} \text{ FU NaCl}

There are \boxed{3.4 \times 10^{22} \text{ FU NaCl}} in 3.6 g of NaCl.

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3 years ago
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