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3 years ago

1/2-1/4 help?:) uhhhh thankssss

Mathematics

1 answer:

sertanlavr [38]3 years ago

4 0

1/2 - 1/4 = 2/4 - 1/4 = 1/4

I hope this helps!

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Find all zeros of x^4+x

Yuri [45]

Answer:

-1 and 0

Step-by-step explanation:

X ^4+x = 0;

x*(x^3+1)=0;

x*[(x^3-x)+(x+1)]=0;

x*[x(x-1)(x+1)+(x+1)]=0;

x*(x+1)(x^2-x+1)=0;

Since x^2-x+1=0 has no intersection with the X-axis, there is no x value such that y=0

x=0 or -1

4 0

2 years ago

two adjacent angles of a parallelogram are in the ratio 5:2: . find all the angles of the parallelogram

kicyunya [14]

<h2>Given :-</h2>

Two adjacent angles of a parallelogram are in the ratio of 5 : 2.

What is the all angles of the parallelogram.

<h3 /><h3 /><h2>Solution :-</h2>

Let, the first angles be 5x

And, the second angles will be 2x

As we know that,

★ Sum of all angles = 180° ★

According to the question by using the formula we get,

⇒ 5x+2x=180°

⇒7x=180°

⇒ $\sf x =\: \dfrac{\cancel{180^{\circ}}}{\cancel{7}}$

➠ $\sf\bold{\red{x =\: 25.7^{\circ}}}$

Hence, the required angles are,

First angles = 5x = 5(25.7°) = 128.5°
Second angles = 2(25.7°) = 51.4°

As we know that,

opposite angles in a parallelogram

is equal.

∴ The all angles of a parallelogram is 128.5°,51.4°, 128.5° and 51.4°.

6 0

3 years ago

What’s 18/20 simplified

Savatey [412]

Find the GCD (or HCF) of numerator and denominator

GCD of 18 and 20 is 2

Divide both the numerator and denominator by the GCD

18 ÷ 2

-----------

20 ÷ 2

Reduced fraction:

----

5 0

3 years ago

Read 2 more answers

25 Points ! Write a paragraph proof.<br> Given: ∠T and ∠V are right angles.<br> Prove: ∆TUW ∆VWU

vladimir2022 [97]

Answer:

Δ TUW ≅ ΔVWU ⇒ by AAS case

Step-by-step explanation:

* Lets revise the cases of congruent for triangles

- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ

- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and

including angle in the 2nd Δ

- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ

≅ 2 angles and the side whose joining them in the 2nd Δ

- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles

and one side in the 2ndΔ

- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse

leg of the 2nd right angle Δ

* Lets solve the problem

- There are two triangles TUW and VWU

- ∠T and ∠V are right angles

- LINE TW is parallel to line VU

∵ TW // VU and UW is a transversal

∴ m∠VUW = m∠TWU ⇒ alternate angles (Z shape)

- Now we have in the two triangles two pairs of angle equal each

other and one common side, so we can use the case AAS

- In Δ TUW and ΔVWU

∵ m∠T = m∠V ⇒ given (right angles)

∵ m∠TWU = m∠VUW ⇒ proved

∵ UW = WU ⇒ (common side in the 2 Δ)

∴ Δ TUW ≅ ΔVWU ⇒ by AAS case

7 0

3 years ago

Read 2 more answers

15-(4m - 5) = 32 please help me

atroni [7]

The answer is = -3, hope this helps!

7 0

3 years ago

Read 2 more answers

1/2-1/4￼ help?:) uhhhh thankssss

1/2-1/4 help?:) uhhhh thankssss