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zmey [24]
3 years ago
13

If the measure of angle ACB is 50 degrees, what is the measure of angle AOB

Mathematics
1 answer:
kodGreya [7K]3 years ago
8 0

The answer is 100 degree

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What is the quotient of -3/8and-1/3?
hodyreva [135]

Answer:

9/8

Step-by-step explanation:

the quotient of -3/8 and -1/3

= (-3/8)  /  (-1/3)

= (-3/8) x (-3/1)

= 9/8

8 0
3 years ago
Please help get value of x. I believe it is 7 but idk.
den301095 [7]
The value of x would be 8
3 0
3 years ago
Read 2 more answers
A number that is even and not a multiple of 4 or 6
Anestetic [448]
10 would be the answer I believe.
4 0
3 years ago
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two opposite angles are congruent, necessary or not, and sufficient or not for a quadrilateral to be a parallelogram
hjlf

Answer: Ok here we go

Step-by-step explanation: Consecutive Angles

[insert drawing of irregular quadrilateral BEAR]

If you were to go around this shape in a clockwise direction starting at ∠B, you would next get to ∠E. Those two angles are consecutive. So are all these pairs:

∠E and ∠A

∠A and ∠R

∠R and ∠B

Consecutive angles have endpoints of the same side of the polygon.

Supplementary Angles

Supplementary angles are two angles adding to 180°. In a parallelogram, any two consecutive angles are supplementary, no matter which pair you pick.

Parallelograms

Parallelograms are special types of quadrilaterals with opposite sides parallel. Parallelograms have these identifying properties:

Congruent opposite sides

Congruent opposite angles

Supplementary consecutive angles

If the quadrilateral has one right angle, then it has four right angles

Bisecting diagonals

Each diagonal separates the parallelogram into two congruent triangles

Parallelograms get their names from having two pairs of parallel opposite sides.

Another interesting, and useful, feature of parallelograms tells us that any angle of the parallelogram is supplementary to the consecutive angles on either side of it.

We can use these features and properties to establish six ways of proving a quadrilateral is a parallelogram.

Proving A Quadrilateral is a Parallelogram

Can you be certain? Only by mathematically proving that the shape has the identifying properties of a parallelogram can you be sure. You can prove this with either a two-column proof or a paragraph proof.

Six Ways

Here are the six ways to prove a quadrilateral is a parallelogram:

Prove that opposite sides are congruent

Prove that opposite angles are congruent

Prove that opposite sides are parallel

Prove that consecutive angles are supplementary (adding to 180°)

Prove that an angle is supplementary to both its consecutive angles

Prove that the quadrilateral's diagonals bisect each other

Two-Column Proof

We can use one of these ways in a two-column proof. Bear in mind that, to challenge you, most problems involving parallelograms and proofs will not give you all the information about the presented shape. Here, for example, you are given a quadrilateral and told that its opposite sides are congruent.

Statement Reason:

GO ≅ TA and TG ≅ OA (Given)

Construct segment TO Construct a diagonal

TO ≅ TO Reflexive Property

△GOT ≅ △ TOA Side-Side-Side Postulate: If three sides of one △

are congruent to three sides of another △, then the two △ are congruent

∠GTO ≅ ∠ TOA CPCTC: Corresponding parts of congruent △ are

∠GOT ≅ ∠ OTA congruent

GO ∥ TA and TG ∥ OA Converse of the Alternate Interior Angles

Theorem: If a transversal cuts across two lines and the alternate interior angles are congruent, then the lines are parallel

▱ GOAT Definition of a parallelogram: A quadrilateral

with two pairs of opposite sides parallel

The two-column proof proved the quadrilateral is a parallelogram by proving opposite sides were parallel.

Paragraph Proof

You can also use the paragraph proof form for any of the six ways. Paragraph proofs are harder to write because you may skip a step or leave out an explanation for one of your statements. You may wish to work very slowly to avoid problems.

Always start by making a drawing so you know exactly what you are saying about the quadrilateral as you prove it is a parallelogram.

Here is a proof still using opposite sides parallel, but with a different set of given facts. You are given a quadrilateral with diagonals that are identified as bisecting each other.

[insert drawing of quadrilateral FISH with diagonals HI and FS, but make quadrilateral clearly NOT a parallelogram; show congruency marks on the two diagonals showing they are bisected]

Given a quadrilateral FISH with bisecting diagonals FS and HI, we can also say that the angles created by the intersecting diagonals are congruent. They are congruent because they are vertical angles (opposite angles sharing a vertex point).

Notice that we have two sides and an angle of both triangles inside the quadrilateral. So, we can use the Side-Angle-Side Congruence Theorem to declare the two triangles congruent.

Corresponding parts of congruent triangles are congruent (CPCTC), so ∠IFS and ∠ HSF are congruent. Those two angles are alternate interior angles, and if they are congruent, then sides FI and SH are parallel.

You can repeat the steps to prove FH and IS parallel, which means two pairs of opposite sides are parallel. Thus, you have a parallelogram.

In both proofs, you may say that you already were given a fact that is one of the properties of parallelograms. That is true with both proofs, but in neither case was the given information mathematically proven. You began with the given and worked through the problem, but if your proof "fell apart," then the given may have been wrong.

Since neither our two-column proof or paragraph proof "fell apart," we know the givens were true, and we know the quadrilaterals are parallelograms.

5 0
3 years ago
Find an equation of the plane orthogonal to the line
jolli1 [7]

The given line is orthogonal to the plane you want to find, so the tangent vector of this line can be used as the normal vector for the plane.

The tangent vector for the line is

d/d<em>t</em> (⟨0, 9, 6⟩ + ⟨7, -7, -6⟩<em>t </em>) = ⟨7, -7, -6⟩

Then the plane that passes through the origin with this as its normal vector has equation

⟨<em>x</em>, <em>y</em>, <em>z</em>⟩ • ⟨7, -7, -6⟩ = 0

We want the plane to pass through the point (9, 6, 0), so we just translate every vector pointing to the plane itself by adding ⟨9, 6, 0⟩,

(⟨<em>x</em>, <em>y</em>, <em>z</em>⟩ - ⟨9, 6, 0⟩) • ⟨7, -7, -6⟩ = 0

Simplifying this expression and writing it standard form gives

⟨<em>x</em> - 9, <em>y</em> - 6, <em>z</em>⟩ • ⟨7, -7, -6⟩ = 0

7 (<em>x</em> - 9) - 7 (<em>y</em> - 6) - 6<em>z</em> = 0

7<em>x</em> - 63 - 7<em>y</em> + 42 - 6<em>z</em> = 0

7<em>x</em> - 7<em>y</em> - 6<em>z</em> = 21

so that

<em>a</em> = 7, <em>b</em> = -7, <em>c</em> = -6, and <em>d</em> = 21

4 0
3 years ago
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