Answer:
![(x-3)^2+ (y+5)^2=10](https://tex.z-dn.net/?f=%28x-3%29%5E2%2B%20%28y%2B5%29%5E2%3D10)
Step-by-step explanation:
Given the equation of the circle: ![x^2 + y^2 - 6x + 10y + 24 = 0](https://tex.z-dn.net/?f=x%5E2%20%2B%20y%5E2%20-%206x%20%2B%2010y%20%2B%2024%20%3D%200)
We wish to express it in a Standard form:
We begin by re-arranging:
![x^2 - 6x + y^2 + 10y = - 24](https://tex.z-dn.net/?f=x%5E2%20-%206x%20%2B%20y%5E2%20%20%2B%2010y%20%20%3D%20-%2024)
Next, divide the coefficient of x by 2, square it and add it to both sides.
Do the same for y.
![x^2 - 6x +(-3)^2+ y^2 + 10y+5^2 = - 24+(-3)^2+5^2](https://tex.z-dn.net/?f=x%5E2%20-%206x%20%2B%28-3%29%5E2%2B%20y%5E2%20%20%2B%2010y%2B5%5E2%20%20%3D%20-%2024%2B%28-3%29%5E2%2B5%5E2)
Next, we factorize
![(x-3)^2+ (y+5)^2 = - 24+9+25\\(x-3)^2+ (y+5)^2=10](https://tex.z-dn.net/?f=%28x-3%29%5E2%2B%20%28y%2B5%29%5E2%20%20%3D%20-%2024%2B9%2B25%5C%5C%28x-3%29%5E2%2B%20%28y%2B5%29%5E2%3D10)
This is the standard form.
Answer:
P = 1 / 6
Step-by-step explanation:
Given:-
- A deck has 500 cards
- Numbered from 1-500
Find:-
you are asked to pick three cards, one at a time, what's the probability of each subsequent card being larger than the previous drawn card
Solution:-
- Suppose we draw three cards. We don't care what they actually are, irrespective of number.
- Let the three numbers be a, b, c: Such that:
a < b < c.
- The total possible combinations with 3 numbered cards will be:
a b c
b a c
a c b
b a c
b c a
c a b
- We have 6 possibilities for 3 numbered cards. So the probability of of each subsequent card being larger than the previous drawn card would be:
P = 1 / possible combinations
P = 1 / 6
Answer:
.
Step-by-step explanation: