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hjlf
3 years ago
15

Write the expression as a polynomial (x+1)(x+2)(y–3)

Mathematics
1 answer:
o-na [289]3 years ago
6 0

\text{Use FOIL method:}\ (a+b)(c+d)=ac+ad+bc+bd\\\\(x+1)(x+2)(y-3)=[(x)(x)+(x)(2)+(1)(x)+(1)(2)](y-3)\\\\=(x^2+2x+x+2)(y-3)=(x^2+3x+2)(y-3)\\\\=(x^2)(y)+(x^2)(-3)+(3x)(y)+(3x)(-3)+(2)(y)+(2)(-3)\\\\=\boxed{x^2y-3x^2+3xy-9x+2y-6}

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Lines AB and BC intersect at point B. Ray BD bisects angle ABC. (4x-24) B (x+6) What is the value of x?
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If line AB and BC are intersecting at point B and ray BD bisect the angle ABC, then the value of x is 23

The line AB and BC are intersecting at point B.

Ray BD bisect the  angle ABC

∠ABD = x+8 degrees

∠ABD=∠DBC = x+8

Because the ray BD bisect the ∠ABC, so ∠ABD and ∠DBC will be equal

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Because both are vertically opposite angles

Substitute the values in the equation

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2x-4x = -30-16

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x = 23

Hence, if line AB and BC are intersecting at point B and ray BD bisect  the angle ABC, then the value of x is 23

The complete question is

Line AB and BC are intersecting at point B and ray BD bisect the angle ABC. What is the value of x?

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