Question

PLEASE HURRY I NEED HELP SOS!!!!!!!! (15 POINTS)

Answer 1

Answer:

0, π, 7π/6, 11π/6   on the interval 0 ≤ ø <2π.

Step-by-step explanation:

sinø + 1 = cos2ø

Use the identity cos 2o = 1 - 2 sin^2 o:

sin o + 1 = 1 - 2 sin^2 o

2sin^2 o + sin o + 1 - 1 = 0

2 sin^2 o + sin o = 0

sin o (2 sin 0 + 1) = 0

Therefore sin o = 0 or sin o = -1/2.

For sin o = 0 , o = 0, π radians.

For sin o = - 1/2, o = 7π/6, 11π/6 radians.