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3 years ago

PLEASE HURRY I NEED HELP SOS!!!!!!!! (15 POINTS)

Mathematics

1 answer:

yaroslaw [1]3 years ago

8 0

Answer:

0, π, 7π/6, 11π/6 on the interval 0 ≤ ø <2π.

Step-by-step explanation:

sinø + 1 = cos2ø

Use the identity cos 2o = 1 - 2 sin^2 o:

sin o + 1 = 1 - 2 sin^2 o

2sin^2 o + sin o + 1 - 1 = 0

2 sin^2 o + sin o = 0

sin o (2 sin 0 + 1) = 0

Therefore sin o = 0 or sin o = -1/2.

For sin o = 0 , o = 0, π radians.

For sin o = - 1/2, o = 7π/6, 11π/6 radians.

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What is the solution to the equation <br> 13×3/4+x=7(1/4)

yan [13]

I'm going to assume you mean:

13 * (3/4) + x = 7 * (1/4)

Let's go ahead and simplify the right side.

7 * (1/4) = 1.75

So now we have:

13 * (3/4) + x = 1.75

Now let's take care of the right side. Multiplication before addition.

13 * (3/4) = 9.75

9.75 + x = 1.75

To isolate x, we subtract 9.75 from both sides.

9.75 - 9.75 + x = 1.75 - 9.75

x = -8

Hopefully I spaced this well. \('-')/

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3 years ago

2 345 000 000 in scientific notation

grigory [225]

2.345 * 10^9 . Hope this helps

6 0

3 years ago

Determine the values of the constants b and c so that the function given below is differentiable. f(x)={2xbx2+cxx≤1x>1

Lera25 [3.4K]

Assuming the function is

$f(x)=\begin{cases}2x&\text{for }x\le1\\bx^2+cx&\text{for }x>1\end{cases}$

For $f(x)$ to be differentiable, it necessarily has to be continuous. For this condition to be met, we need

$\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^+}f(x)=f(1)$
$\iff\displaystyle\lim_{x\to1}2x=\lim_{x\to1}(bx^2+cx)$
$\iff2=b+c$

For the derivative to exist, the one-sided limits of the derivative must also exist and be equal. We have

$f'(x)=\begin{cases}2&\text{for }x1\end{cases}$

$\displaystyle\lim_{x\to1^-}2=\lim_{x\to1^+}(2bx+c)$
$\iff2=2b+c$

Now we solve for $b$ and $c$ :

$\begin{cases}b+c=2\\2b+c=2\end{cases}\implies b=0,c=2$

5 0

4 years ago

In a survey of adults who follow more than one sport, 30% listed football as their favorite sport. You survey 15 adults who foll

maxonik [38]

Answer: 0.5

Step-by-step explanation:

Binomial probability formula :-

$P(x)=^nC_x\ p^x(q)^{n-x}$ , where P(x) is the probability of getting success in x trials , n is the total trials and p is the probability of getting success in each trial.

Given : The probability that the adults follow more than one game = 0.30

Then , q= 1-p = 1-0.30=0.70

The number of adults surveyed : n= 15

Let X be represents the adults who follow more than one sport.

Then , the probability that fewer than 4 of them will say that football is their favorite sport,

$P(X\leq4)=P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)\\\\=^{15}C_{0}\ (0.30)^0(0.70)^{15}+^{15}C_{1}\ (0.30)^1(0.70)^{14}+^{15}C_{2}\ (0.30)^2(0.70)^{13}+^{15}C_{3}\ (0.30)^3(0.70)^{12}+^{15}C_{4}\ (0.30)^4(0.70)^{11}\\\\=(0.30)^0(0.70)^{15}+15(0.30)^1(0.70)^{14}+105(0.30)^2(0.70)^{13}+455(0.30)^3(0.70)^{12}+1365(0.30)^4(0.70)^{11}\\\\=0.515491059227\approx0.5$