Answer:
INF for first while D for second
Step-by-step explanation:
Ok I think I read that integral with lower limit 1 and upper limit infinity
where the integrand is ln(x)*x^2
integrate(ln(x)*x^2)
=x^3/3 *ln(x)- integrate(x^3/3 *1/x)
Let's simplify
=x^3/3 *ln(x)-integrate(x^2/3)
=x^3/3*ln(x)-1/3*x^3/3
=x^3/3* ln(x)-x^3/9+C
Now apply the limits of integration where z goes to infinity
[z^3/3*ln(z)-z^3/9]-[1^3/3*ln(1)-1^3/9]
[z^3/3*ln(z)-z^3/9]- (1/9)
focuse on the part involving z... for now
z^3/9[ 3ln(z)-1]
Both parts are getting positive large for positive large values of z
So the integral diverges to infinity (INF)
By the integral test... the sum also diverges (D)
Answer:
6.85
Step-by-step explanation:
a^2+3.4^2=7.65^2
a^2=46.96
a=6.85
I used Pythagorean theorem, I hope I am right
Answer:
See the equation simplified below.
Step-by-step explanation:
The equation simplifies to the following equations:
4[x + 2(3x - 7)] = 22x - 65
4[x+6x-14] = 22x - 65
4x+24x - 56 = 22x - 65
28x - 56 = 22x - 65
6x - 56 = -65
6x = -9
x = -3/2
Answer:
3x + 12 + x = 180
4x +12 = 180
4x = 168
x = 42
(I'm guessing you're in a different timezone than I am because it's already 3:35 here)
Answer: 38760
Step-by-step explanation:
Given : The number of employees in the company = 20
The number of employees will be selected by company owner to give bonus = 6
We know that the combination of n things taking r at a time is given by :-
Then, the number of different sets of employees could receive bonuses is given by :-
Hence, the number of different sets of employees could receive bonuses is 38760.
