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jolli1 [7]
3 years ago
9

2 345 000 000 in scientific notation​

Mathematics
1 answer:
grigory [225]3 years ago
6 0
2.345 * 10^9 . Hope this helps
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A tessellation has 2 pairs of congruent angles around the point of intersection. The measure of each of one pair of congruent an
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9514 1404 393

Answer:

  152°

Step-by-step explanation:

If two pairs of congruent angles total 360°, then the different angles must total 180°. The other angle measure is 180° -28° = 152°.

The measure of each angle in the other congruent pair is 152°.

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2 years ago
What is 30% of 10/16
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Answer;  30% of 10/16 is

0.1875

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Question 8 -
FinnZ [79.3K]

Answer:

Her wage on the 8th day is $105 ⇒ answer d

Step-by-step explanation:

* <em>Lets explain how to solve the problem</em>

- The average of set of data = The sum of data/the number of data

- The sum of data = the average of set of data × the number of data

∵ Cindy worked for 15 consecutive days

∵ She is earning an average wage of $91 per day

∴ Her total earning = 91 × 15 = $1365

∵ Her average earning during the first 7 days is $87 per day

∴ Her total earning in the first 7 days = 87 × 7 = $609

∵ Her average earning during the last 7 days is $93 per day

∴ Her total earning in the last 7 days = 93 × 7 = $651

- Her total earning in the 14 days is the sum of the earning in the

 first 7 days and the earning during the last 7 days

∵ Her total earning in the 14 days = 609 + 651 = $1260

∵ Her total earning in the 15 days is $1365

- To find her wage on the 8th day subtract her wage of the 14 days

  from her wage of the 15 days

∴ Her wage on the 8th day = 1365 - 1260 = $105

* Her wage on the 8th day is $105

7 0
2 years ago
Suppose a class of 50 students has 20 males and 30 females. The insturctor will pick 1 (different) student to compete in 3 diffe
Pie

Answer:

Step-by-step explanation:

Total = 50

Males = 20

Females = 30

a) P(exactly 1 female) = P(1 female , 2 male)

(30C1 * 20C2) / (50C3) = 30*190/19,600 = 0.2908

b) P(at least 2 males) = 1 - (P(0 males) + P(1 males))

= 1 - 30C3 * 20C0/50C3 - 30C2 * 20C1/50C3

= 1 - 4060*1/19,600 - 435*20/19,600 = 6840/19600 = 0.3489

4 0
3 years ago
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a classroom has a length of 20 feet and a width of 30 feet. The headmaster decided that tiles will look good in that class. if e
iogann1982 [59]
The area of the room must equal the sum of the areas of the tiles...

20*30=n(2*3)

600=6n

n=100

So 100 tiles are needed.
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2 years ago
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