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Fiesta28 [93]
3 years ago
7

−k+2(−2k−5) simplify

Mathematics
2 answers:
Agata [3.3K]3 years ago
5 0

Answer:

-k-14

Step-by-step explanation:

Use distributive property and then just carry on and combine like terms.

BARSIC [14]3 years ago
4 0

Answer:

-5k - 10

Step-by-step explanation:

-k + 2 ( -2k - 5 )

= -k - 4k - 10

= -5k - 10

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Maya is flying a kite, holding her hands a distance of 3.5 feet above the ground and letting all the kite’s string play out. She
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The kite is 73.4 feet above the ground.

Step-by-step explanation:

125 sin 34=

Cross multiply.

x=69.899112...

x=69.899112...

{Add 3.5, the distance from the ground to her hand:}

Add 3.5, the distance from the ground to her hand:

69.899112...+3.5=

73.399112...

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3 years ago
(2 4/10+8 4/5)-3 1/5 equals what whole number
FromTheMoon [43]

Answer:

8

Step-by-step explanation:

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Please help me with this math problem!! Will give brainliest!! :) (Pictures below)
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Step-by-step explanation:

1. Y-axis (the vertical one) is money

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What is this answer?
zhannawk [14.2K]

I'm NOT 100% confident in my answers.

Graph 1:

Range: Option B

Graph 2:

Range: Option A

The range has to start at zero since that's the lowest point we can go, only one with zero is first option.

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8 0
3 years ago
Solve the rational function of (check image) and check for extraneous solutions
Oxana [17]

Answer:

Option A is correct.

i.e. x = 1, x = 0 is an extraneous solution.

Step-by-step explanation:

Given the expression

\frac{5}{x}=\frac{4x+1}{x^2}

Solving the rational function

\frac{5}{x}=\frac{4x+1}{x^2}

Apply fraction across multiply: if \frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c

5x^2=x\left(4x+1\right)

Subtract x(4x+1) from both sides

5x^2-x\left(4x+1\right)=x\left(4x+1\right)-x\left(4x+1\right)

Simplify

5x^2-x\left(4x+1\right)=0

5x² - 4x² - x = 0

x² - x = 0

Factor x² - x = x(x-1)

so

x(x-1) = 0

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

x=0\quad \mathrm{or}\quad \:x-1=0

Thus, the solution to the equation is:

x=0,\:x=1

But, it is clear that if we substitute x = 0, the equation becomes undefined because we can not have the denominator to be 0.

In other words, the equation is undefined for x = 0

Thus, x = 0 is an extraneous solutions.

Therefore, option A is correct.

i.e. x = 1, x = 0 is an extraneous solution.

5 0
3 years ago
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