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stiks02 [169]
3 years ago
8

The weight of one serving of trail mix is 2.5 ounces. How many servings are there in 22.5 ounces of trail mix?

Mathematics
1 answer:
Delicious77 [7]3 years ago
3 0

Answer:

9

Step-by-step explanation:

Divide 22.5 by 2.5

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John bought a used truck for $4,500. He made an agreement with the dealer to put $1,500 down and make payments of $350 for the n
musickatia [10]

Answer:

(D) 36%

Step-by-step explanation:

Actual cost of truck = $4500

Down payment = $1500

Money left to be paid = 4500-1500 =  $3000

A = Monthly payments = 350

n = 10

Principal value (P) = 3000

Using formula,

A= \frac{Pr(1+r)^{n}}{(1+r)^{n}-1}

350 =\frac{3000r(1+r)^{10}}{(1+r)^{10}-1}

       = 36% (approx)

Hence (D) is correct.

5 0
3 years ago
Given that f(x)= x2+3 and g(x)= x+4/3 solve for (f(g(x)) when x =2
Savatey [412]
\bf \begin{cases}
f(x)=x^2+3\\\\
g(x)=x+\cfrac{4}{3}
\end{cases}
\\\\\\
\boxed{x=2}\qquad g(2)=(2)+\cfrac{4}{3}\implies \boxed{g(2)=\cfrac{10}{3}}
\\\\\\
f(~~g(x)~~)=[g(x)]^2+3\implies f(~~g(2)~~)=[g(2)]^2+3
\\\\\\
f(~~g(2)~~)=\left[ \boxed{\frac{10}{3}} \right]^2+3\implies f(~~g(2)~~)=\cfrac{10^2}{3^2}+3
\\\\\\
f(~~g(2)~~)=\cfrac{100}{9}+3\implies f(~~g(2)~~)=\cfrac{100+27}{9}
\\\\\\
f(~~g(2)~~)=\cfrac{127}{9}
7 0
3 years ago
1. How do you identify the terms in an expression? 2. How do you determine the coefficient of a term if you don’t see a number i
Sonbull [250]
I hope you have good luck!!
7 0
3 years ago
A 2.2 kg ball strikes a wall with a velocity of 7.4 m/s to the left. The ball bounces off with a velocity of 6.2 m/s to the righ
Naya [18.7K]

Answer:

The constant force exerted on the ball by the wall is 119.68 N.

Step-by-step explanation:

Consider the provided information.

It is given that the mass of the ball is m = 2.2 kg

The initial velocity of the ball towards left is 7.4 m/s

So the momentum of the ball when it strikes is = 2.2\times 7.4=16.28

The final velocity of the ball is -6.2 m/s

So the momentum of the ball when it strikes back is = 2.2\times -6.2=-13.64

Thus change in moment is: 16.28-(-13.64)=29.92

The duration of force exerted on the ball t = 0.25 s

Therefore, the constant force exerted on the ball by the wall is:

\frac{29.92}{0.25}=119.68

Hence, the constant force exerted on the ball by the wall is 119.68 N.

6 0
4 years ago
Solve for the given variable 3(2x+5)=4x+21
Nookie1986 [14]

Answer:

x=3

Step-by-step explanation:

3(2x+5)=4x+21

6x+15=4x+21

-4x            -4x

2x+15= 21

     -15    -15

2x=6

2     2

<h2>x=3                          Hope that helped!!!!</h2>
6 0
3 years ago
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