3 years ago

Six trigonometric functions when an angles coordinates are (12,5)

1 answer:

4 0

X = 12 y = 5... to get r you'll add 12^2 + 5^2 = r^2. From there you just place the numbers in trig functions.. sin= y/r cos=x/r tan=y/x csc=r/y and so on. If you draw the triangle it's much easier than it looks here.

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What is the area of the figure?

mash [69]

Check the picture below.

$\bf \textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh\qquad \qquad A=\cfrac{1}{2}(12\sqrt{2})(12\sqrt{2})\implies A=6\sqrt{2}\cdot 12\sqrt{2} \\\\\\ A=6\cdot 12\sqrt{2}\cdot \sqrt{2}\implies \implies A=72(\sqrt{2})^2\implies A=72\cdot 2\implies A=144$