Answer:
The correct factored form is (x -2)(x - 5)
Step-by-step explanation:
When looking for the numbers to go in the parenthesis, find numbers that multiply to the final term and add up to the middle term. To find these, list out the factors of 10.
1 * 10
-1 * -10
2 * 5
-2 * -5
As you can see, -2 and -5 add up to -7. So we select these to go in the parenthesis with x.
(x - 2)(x - 5)
Answer:
1m 54cm
Step-by-step explanation:
10 students at 1m 40cm
15 students at 1m 58cm
13 students at 1m 60cm
Keep in mind that ratio between cm to m is 1cm/0.01m.
So let find the average by converting cm to m first for the 38 students.
10 students: 1m + (40cm)(0.01m/1cm) => 1.4 m
15 students: 1m + 58cm(0.01m/1cm) => 1.58 m
13 students: 1m 60cm(0.01m/1cm) => 1.60 m
so the average is weighted:
(10*1.4 +15*1.58 + 13(1.6))/38
Therefore the average model height is 1.54 m or 1m 54cm
Answer:
657483920
Step-by-step explanation:
this is incorrect
Final Answer:
Steps/Reasons/Explanation:
There are two methods of solving this problem. Slope-intercept form and Point-slope form. I will be using the Slope-intercept form to solve this problem.
<u>Step 1</u>: Substitute slope from the original line ( in this case) into the slope-intercept equation.
<u>Step 2</u>: Substitute the given point into the x and y values.
<u>Step 3</u>: Solve for b (the y-intercept).
=
<u>Step 4</u>: Substitute this value for b in the slope-intercept form equation.
~I hope I helped you :)~
Answer:
The answer is below
Step-by-step explanation:
a) Let the width be represented as w and the length be represented as l.
The perimeter of the sand box = 2(l + w)
Since there is 400 feet of material for the sides of the sandbox, hence:
400 = 2(l + w)
200 = l + w
l = 200 - w
The area (A) is:
A = length * width
A = (200 - w) * w
A(w) = 200w - w²
b) The maximum area is at A'(w) = 0. Hence:
A'(w) = 200 - 2w
200 - 2w = 0
2w = 200
w = 100 feet.
l = 200 - w = 200 - 100
l = 100 feet.
Area = length * width = 100 * 100 = 10000 feet²
The maximum area of the sandbox is 10000 feet², with a length of 100 feet and width of 100 feet.