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Nadusha1986 [10]
3 years ago
11

Can someone help me solve this

Mathematics
1 answer:
Phantasy [73]3 years ago
6 0
The picture is white I can’t help you sorry
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Complete the scaling for each number line or set of axes.<br> 32<br> 64
vodka [1.7K]
The answer will be C.
6 0
2 years ago
Simplify the expression 2 (2 + 4y) + 3x.<br> PLS ANSWER ASAP DUE 9:20
Novay_Z [31]

Answer:

5x+8y

Step-by-step explanation:

We can first open the brackets by using the distrubitive propety.

2(x+4y)+3x

2x+8y+3x

Now we can combine like terms.

5x+8y.

I combined the 3x and the 2x. This works because imagined I have 3 of something then I got 2 more of that something I would now have 5 of that something.

Hoped this helped,

JoeLouis2

7 0
3 years ago
Add.
Elina [12.6K]

Answer:

2x²+4x-4

Step-by-step explanation:

hope this helps,

that's how you can add, check out the image i uploaded

8 0
2 years ago
Read 2 more answers
If 2 X + 1 ,2 x-1 and 3 X + 4 are in AP find the value of x​
julia-pushkina [17]

Answer:

x = - 7

Step-by-step explanation:

Given that the terms are in AP , then

a₃ - a₂ = a₂ - a₁ , substitute values

3x + 4 - (2x - 1) = 2x - 1 - (2x + 1) ← distribute and simplify both sides

3x + 4 - 2x + 1 = 2x - 1 - 2x - 1

x + 5 = - 2 ( subtract 5 from both sides )

x = - 7

6 0
3 years ago
Please help me with this math!
wel

Answer:

Please check the explanation.

Step-by-step explanation:

Given the polynomial function

f\left(x\right)\:=x^3+2x^2-16x-32

Let us determine the factors by solving

\:\left0\right\:=x^3+2x^2-16x-32\:

\left(x+2\right)\left(x+4\right)\left(x-4\right)=0

Using the zero factor principle:

if  ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

x+2=0\quad \mathrm{or}\quad \:x+4=0\quad \mathrm{or}\quad \:x-4=0

Thus, (x+2) (x+4) and (x-4) are the factors of the polynomial function.

Therefore,

YES

  • (x+2)
  • (x+4)
  • (x-4)

And (x-2) (x+6) are not the factors of the polynomial function.

Therefore,

YES

  • (x-2)
  • (x+6)
3 0
3 years ago
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