9514 1404 393
Answer:
9.5°, yes
Step-by-step explanation:
The relevant trig relation is ...
Tan = Opposite/Adjacent
The distance opposite the angle of elevation is the plane's height, 500 m. The distance adjacent to the angle of elevation is the horizontal distance to the plane, 3 km = 3000 m. Then the angle is found from ...
tan(α) = 500/3000 = 1/6
α = arctan(1/6) ≈ 9.46°
The plane is approaching at an angle of 9.46°. It is safe to land, since that angle is less than 15°.
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<em>Additional comment</em>
The usual descent angle for most commercial air traffic is 3°. Some airport geography demands it be different (steeper). A higher descent angle can put undue stress on the landing gear.
Answer:
y=5-5/4x
Step-by-step explanation:
slope-intercept form: y=mx+b (m= slope, b= y-intercept)
5x + 4y = 20
4y=20-5x
simplify
y=5-5/4x
It is a rational number in the form of a decimal fraction.
1 2/3y = 3x
A picture is worth a thousand words
The trick to solving problems with mixed units is to convert all of them into one unit or another, so:
There are 12 inches in a foot, so 72 inches = 6 feet.
To find the perimeter of a polygon, sum its sides.
Perimeter = 2 + 5 + 6 = 13 feet.
To find the area of a right triangle (which I assume the one in the picture is), we can use the following equation: A = 0.5 * base * height
There are 3 feet to one yard, so 6 feet = 2 yards.
Area = 0.5 * 2 * 1 = 1 yard^2
