To complete the table it is necessary to know the possibilities that the sergeant has to change or remain in an intersection. The probabilities (depending on the box) are:
<h3>How to calculate the probability of intersection change?
</h3>
To know the probability of intersection change, it is necessary to locate the police officer at one of the intersections. Subsequently, count how many possibilities of change you have, for example: 3 possibilities and finally add the possibility of remaining in the intersection as shown below:
- Intersection 3 has 3 possibilities of changing towards intersections 2, 8 and 4. Additionally, it has the possibility of staying at intersection 3, that is, it has 4 possible decisions.
To know the probability we divide the number 1 (because it is only a decision that we have to make) and divide it by the number of possibilities (4).
According to the image we can infer that in some intersections they only have 3, 4 and 5 possibilities, so the probability of change will be different as shown below:
- 1 ÷ 3 = 0.33
- 1 ÷ 4 = 0.25
- 1 ÷ 5 = 0.2
Learn more about probabilities in: brainly.com/question/8069952
A represents 12!
12! = 12 * 11 * 10 * 9 * ... (down to 1)
Answer:
![Weighted\ Average = 73](https://tex.z-dn.net/?f=Weighted%5C%20Average%20%3D%20%2073)
Step-by-step explanation:
Given
![Lab = 21\%](https://tex.z-dn.net/?f=Lab%20%3D%2021%5C%25)
![Tests = 25\%](https://tex.z-dn.net/?f=Tests%20%3D%2025%5C%25)
![Exam = 29\%](https://tex.z-dn.net/?f=Exam%20%3D%2029%5C%25)
![Lab\ Score = 60](https://tex.z-dn.net/?f=Lab%5C%20Score%20%3D%2060)
![First\ Test = 81](https://tex.z-dn.net/?f=First%5C%20Test%20%3D%2081)
![Second\ Test = 69](https://tex.z-dn.net/?f=Second%5C%20Test%20%3D%2069)
![Exam = 79](https://tex.z-dn.net/?f=Exam%20%3D%2079)
Required
The weighted average
To do this, we simply multiply each score by the corresponding worth.
i.e.
![Weighted\ Average = Lab\ worth * Lab\ score + Tests\ worth * Tests\ score.....](https://tex.z-dn.net/?f=Weighted%5C%20Average%20%3D%20%20Lab%5C%20worth%20%2A%20Lab%5C%20score%20%2B%20Tests%5C%20worth%20%2A%20Tests%5C%20score.....)
So, we have:
![Weighted\ Average = 21\% * 60 + 25\% * 81 + 25\% * 69 + 29\% * 79](https://tex.z-dn.net/?f=Weighted%5C%20Average%20%3D%20%2021%5C%25%20%2A%2060%20%2B%2025%5C%25%20%2A%2081%20%2B%2025%5C%25%20%2A%2069%20%2B%2029%5C%25%20%2A%2079)
Using a calculator, we have:
![Weighted\ Average = 73.01](https://tex.z-dn.net/?f=Weighted%5C%20Average%20%3D%20%2073.01)
--- approximated
Answer:
Radius = 504units
Step-by-step explanation:
Angle = 10°
Length of arc = 28π units
L = ∅/360 × 2πr
28π = 10/360 × 2πr
28π = 1/36 × 2πr
2πr = 28π × 36
π cancelled off.......
2r = 28 × 36
r = (28 × 36)/2
r = 28 × 18
r = 504units