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Nimfa-mama [501]
3 years ago
14

Write the slope-intercept form of the equation that passes through the point (1,5) and is perpendicular to the line y =-x + 3

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
4 0

Answer:

y = -1/7x - 23/7

Step-by-step explanation:

Step 1: Find slope <em>m</em>

m = (-4 + 3)/(5 + 2)

m = -1/7

y = -1/7x + b

Step 2: Find <em>b</em>

-3 = -1/7(-2) + b

-3 = 2/7 + b

b = -23/7

Step 3: Rewrite equation

y = -1/7x - 23/7

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That means for those values of x, less than or equal to -3, this is the function.

So, f(-3) = (-3)² + 2(-3) = 9 - 6 = 3

Now, f(-1) :

From the given data, we see it is: f(x) = 2 (\frac{1}{3} )^{2x}

We take this because -1 lies between -3 and 4.

Now, f(-1) = 2 (\frac{1}{3} )^{2(-1)}

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f (4) = \frac{2(4)-5}{4-7} = \frac{3}{-3} = -1

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