Since it is given that the reduction in the amount of waste each week is linear, it is conclusive that these data are also in arithmetic sequence. First, determine the common difference (d)
d = (a10 - a5) / (10 - 5)
Subsituting the known values,
d = (30 - 40) / 5 = -2
To determine any term (at) of the arithmetic sequence,
at = a1 + (n - 1) x d
Solve for a1 by using either the given a5 or a10,
40 = a1 + (5 -1) x -2 ; a1 = 48
The equation becomes,
at = 48 + -2(n -1)
The answer is probably C or D
The answer is C!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
z = -2.85
Step-by-step explanation:
Since the number of nuts per can is normally distributed:
Mean number of nuts (μ)= 500 nuts
Standard Deviation (σ)= 20 nuts
X = 443 nuts
For any given number of nuts X, the z-score is given by:
The z-score for this can of nuts with 443 nuts is -2.85.