All categories

3 years ago

12 out of 15 students play in the school band. In a class of 45 students, how many do NOT play in the band? |

Mathematics

1 answer:

jek_recluse [69]3 years ago

3 0

Answer:36

becuse if you maltiply 15 by 3 it makes 45 and you can maltiply 12 by 3 and you will get your answer

You might be interested in

a recipe for 1 loaf of bread calls for 2 cups of flour, 12 tablespoons of water, and 1 teaspoon of salt. The recipe can be scale

natulia [17]

Answer:

Step-by-step explanation:

A recipe for 1 loaf of bread calls for 2 cups of flour, 12 tablespoons of water and 1 teaspoon of salt.

Therefore, if we add 2 loaves of bread then double of ingredients will be required for the recipe.

In the same way if 4 loaves of bread have been added, 4 times ingredients will be required.

If 3 cups of flour are added then 3 times of other ingredients will be required.

So the table will be,

Number of loaves Cups of flour Tablespoons of water Teaspoons of salt

1 2 12 1

2 4 24 2

4 8 48 4

3 6 36 3

4 0

2 years ago

Please help me I'm not sure what the answer is

gogolik [260]

Step-by-step explanation:

yes yours answer is correct .

4 0

2 years ago

1. Sally said that when you add or subtract positive or negative decimals, you can change the order of the decimals and still ge

siniylev [52]

Always true because addition and subtraction is commutative
-6.2-(-3.96) = -2.24
-3.96-(-6.2)= -2.24
5.71+2.84=8.55
2.84+5.71=8.55
Hope this helped :)

3 0

2 years ago

If y=-12 when x=9 find y when x=-4

Monica [59]

Answer:

16/3

Step-by-step explanation:

6 0

3 years ago

You would like to know whether forwards in a basketball league average the same (or different) numbers of points than the overal

Akimi4 [234]

Answer:

The critical t-value for such a test given an alpha level of 0.05 is 2.26

Step-by-step explanation:

Null hypothesis : $H_0:\mu = 7.5$

Alternate hypothesis : $H_a:\mu \neq 7.5$

Population mean = $\mu = 7.5$

Data : 10, 9, 6, 11, 13, 14, 9, 9, 9, and 10

Mean = $\bar{x}=\frac{\text{Sum of all observations}}{\text{no. of observations}}$

Mean = $\frac{10+9+6+11+13+14+9+9+ 9+ 10}{10}$

Mean =10

Standard deviation : $\sqrt{\frac{\sum(x-\bar{x})^2}{n}}$

Standard deviation : $\sqrt{\frac{(10-10)^2+(9-10)^2+(6-10)^2+(11-10)^2+(13-10)^2+(14-10)^2+(9-10)^2+(9-10)^2+(9-10)^2+(10-10)^2}{10}}$

Standard deviation s :2.144

$t = \frac{x-\mu}{\frac{s}{\sqrt{n}}}t = \frac{10-7.5}{\frac{2.144}{\sqrt{10}}}t=3.687$

Df = n-1 = 10-1 = 9

T critical = $t_{(df,\alpha)}=t_(9,0.05)=2.26$

T calculated > T critical

So, We failed to accept null hypothesis

Hence the critical t-value for such a test given an alpha level of 0.05 is 2.26

5 0

3 years ago

12 out of 15 students play in the school band. In a class of 45 students, how many do NOT play in the band? |​

12 out of 15 students play in the school band. In a class of 45 students, how many do NOT play in the band? |