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3 years ago

You spin a spinner numbered 1 through 10. Find the probability of landing on an even number.

Mathematics

2 answers:

Neporo4naja [7]3 years ago

7 0

Answer:

50%

Step-by-step explanation:

Half the numbers are even and half are odd so you have 50% chance for either one.

DENIUS [597]3 years ago

6 0

Answer:

probability of landing on purple and pink. Find the missing probability. get ... numbered 1 through 5. Predict how many times out of 240 spins the spinner is most likely to stop on an odd number. odd ... Answer: red marbles. D. 10 total blue marbles green marbles. 1 2 2 2 2 ... You receive a less expensive prize if you spin and.

Step-by-step explanation:

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A rule for creating a pattern is given in equation form below.

svetoff [14.1K]

ANSWER B

16=22-6

Do the math on paper and you should get it.

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3 years ago

Read 2 more answers

Finish the pattern<br> (8,5), (2,-1), (0,-3), (-9,-12), (5 (1/2), ____)

tensa zangetsu [6.8K]

Positive slope.Non proportional

Starting at (-9,-12) (0,-3),(2,-1),(5 1/5.2),(8,5)

(5 1/5,2)

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3 years ago

LOTS OF POINTS GIVING BRAINLIEST I NEED HELP PLEASEE

Sidana [21]

Answer:

Segment EF: y = -x + 8

Segment BC: y = -x + 2

Step-by-step explanation:

Given the two similar right triangles, ΔABC and ΔDEF, for which we must determine the slope-intercept form of the side of ΔDEF that is parallel to segment BC.

Upon observing the given diagram, we can infer the following corresponding sides:

$\displaystyle\mathsf{\overline{BC}\:\: and\:\:\overline{EF}}$

$\displaystyle\mathsf{\overline{BA}\:\: and\:\:\overline{ED}}$

$\displaystyle\mathsf{\overline{AC}\:\: and\:\:\overline{DF}}$

We must determine the slope of segment BC from ΔABC, which corresponds to segment EF from ΔDEF.

<h2>Slope of Segment BC:</h2>

In order to solve for the slope of segment BC, we can use the following slope formula:

$\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}} }$

Use the following coordinates from the given diagram:

Point B: (x₁, y₁) = (-2, 4)

Point C: (x₂, y₂) = ( 1, 1 )

Substitute these values into the slope formula:

$\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}}\:=\:\frac{1\:-\:4}{1\:-\:(-2)}\:=\:\frac{-3}{1\:+\:2}\:=\:\frac{-3}{3}\:=\:-1}$

<h2>Slope of Segment EF:</h2>

Similar to how we determined the slope of segment BC, we will use the coordinates of points E and F from ΔDEF to find its slope:

Point E: (x₁, y₁) = (4, 4)

Point F: (x₂, y₂) = (6, 2)

Substitute these values into the slope formula:

$\displaystyle\mathsf{Slope\:(m)\:=\:\frac{y_2 \:-\:y_1}{x_2 \:-\:x_1}}\:=\:\frac{2\:-\:4}{6\:-\:4}\:=\:\frac{-2}{2}\:=\:-1}$

Our calculations show that segment BC and EF have the same slope of -1. In geometry, we know that two nonvertical lines are <u>parallel</u> if and only if they have the same slope.

Since segments BC and EF have the same slope, then it means that $\displaystyle\mathsf{\overline{BC}\:\: | |\:\:\overline{EF}}$ .

<h2>Slope-intercept form:</h2><h3><u>Segment BC:</u></h3>

The <u>y-intercept</u> is the point on the graph where it crosses the y-axis. Thus, it is the value of "y" when x = 0.

Using the slope of segment BC, m = -1, and the coordinates of point C, (1, 1), substitute these values into the <u>slope-intercept form</u> (y = mx + b) to solve for the y-intercept, <em>b. </em>

y = mx + b

1 = -1( 1 ) + b

1 = -1 + b

Add 1 to both sides to isolate b:

1 + 1 = -1 + 1 + b

2 = b

Hence, the <u><em>y-intercept</em></u> of segment BC is: <em>b</em> = 2.

Therefore, the linear equation in <u>slope-intercept form of segment BC</u> is:

⇒ y = -x + 2.

<h3><u /></h3><h3><u>Segment EF:</u></h3>

Using the slope of segment EF, <em>m</em> = -1, and the coordinates of point E, (4, 4), substitute these values into the <u>slope-intercept form</u> to solve for the y-intercept, <em>b. </em>

y = mx + b

4 = -1( 4 ) + b

4 = -4 + b

Add 4 to both sides to isolate b:

4 + 4 = -4 + 4 + b

8 = b

Hence, the <u><em>y-intercept</em></u> of segment BC is: <em>b</em> = 8.

Therefore, the linear equation in <u>slope-intercept form of segment EF</u> is:

⇒ y = -x + 8.

8 0

2 years ago

I need help with number 1-4 I don’t understand..

Karo-lina-s [1.5K]

Answer:

109°, obtuse
131°, obtuse
53°, acute
124°, obtuse

Step-by-step explanation:

You are exected to know the relationships of angles created where a transversal crosses parallel lines.

Corresponding angles are equal (congruent).
Adjacent angles are supplementary, as are any linear pair.
Opposite interior (or exterior) angles are equal (congruent).

The appearance of the diagram often gives you a clue.

You also expected to know the name (or category) of angles less than, equal to, or greater than 90°. Respectively, these are <em>acute</em>, <em>right</em>, and <em>obtuse</em> angles.

1. Adjacent angles are supplementary. The supplement of the given angle is 109°, so x will be obtuse.

2. Opposite exterior angles are equal, so y will be 131°. It is obtuse.

3. Opposite interior angles are equal, so w will be 53°. It is acute.

4. Corresponding angles are equal, so x will be 124°. It is obtuse.

8 0

3 years ago

Select the best answer to complete the sentence. A Rigid Motion or Isometry ______________________.

Dmitry_Shevchenko [17]

Answer: A. preserves length, angle measures and distance between points

Rigid motions or isometries are any of the three transformations below

translation (aka shifting)
rotation
reflection

Any of those three transformations will keep the figure the same size and shape. That means distances between any two points are kept the same, and angle measures are kept the same as well. Everything is kept the same. The only difference is that the figure is in a different location, is rotated somehow, or it is reflected some way. You can use a series of transformations to undo everything to get the original figure back.

If you wanted to change the size of the figure, then you would apply dilation, which isn't an isometry.

5 0

2 years ago