You spin a spinner numbered 1 through 10. Find the probability of landing on an even number.

Mathematics

2 answers:

Neporo4naja [7]3 years ago

7 0

Answer:

50%

Step-by-step explanation:

Half the numbers are even and half are odd so you have 50% chance for either one.

DENIUS [597]3 years ago

6 0

Answer:

probability of landing on purple and pink. Find the missing probability. get ... numbered 1 through 5. Predict how many times out of 240 spins the spinner is most likely to stop on an odd number. odd ... Answer: red marbles. D. 10 total blue marbles green marbles. 1 2 2 2 2 ... You receive a less expensive prize if you spin and.

Step-by-step explanation:

You might be interested in

Write the equation of the circle in standard form: Center (7,0) R=1

Mice21 [21]

Answer:

$(x-7)^2+y^2=1$

Step-by-step explanation:

Hi there!

Equation of a circle: $(x-h)^2+(y-k)^2=r^2$ where the circle is centered at (h,k) and the radius is r

<u>1) Plug in the given center (7,0)</u>

$(x-7)^2+(y-0)^2=r^2\\(x-7)^2+y^2=r^2$

<u>2) Plug in the radius (1)</u>

$(x-7)^2+y^2=1^2\\(x-7)^2+y^2=1$

I hope this helps!

8 0

2 years ago

Mike and Ike are twins. Mike’s age is one more than twice a certain number. Ike’s age is 10 less than triple that same number. F

Misha Larkins [42]

Mike age is 3 less then twice the age of his brother nuke.
M = Mike's age now
N = Nuke's age now
M = 2N - 3

Ten years ago, four times nuke's age was one more mike's age.
M-10 = Mike's age 10 years ago
N-10 = Muke's age 10 years ago
4(N - 10) = 1 + M -10

what are their present ages

find M and N

substitute M = 2N - 3 into 4(N - 10) = 1 + M -10:

4(N - 10) = 1 + [2N - 3] - 10
4N - 40 = 2N - 12
2N = 28
N = 14

M = 2(14) - 3 = 28 - 3 = 25

Mike is 25 and Nuke is 14.

check:
4(14 - 10) = 4(4) = 16 = 26 -10 = 1 + 25 - 10

4 0

2 years ago

Simplify

jeka57 [31]

$\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] ~\dotfill\\\\ x^5\div y^2\times x^3\times y^5\implies \cfrac{x^5}{y^2}\cdot x^3\cdot y^5\implies x^5\cdot y^{-2}\cdot x^3\cdot y^5 \\\\\\ x^{5+3}y^{-2+5}\implies x^8y^3$