Answer:
A. median and mode
B. Mean
C. Mean
d. Positively skewed
Step-by-step explanation:
a. Mean = sum of all values / numbers of values = 1804 / 23 = 78.4. this eliminates the mean and leaves the median and mode, both of which are 62.
Median = middlemost value = 62
Mode = most frequent value = 62
b. Only the Mean would be affected. It would move from 78.4 to 80.6. (calculated as 1853 / 23). The median and mode would not be affected as the 62 would remain the middlemost value and the most frequent.
c. Removing the largest value would result in the mean changing. The mean would now be 73 (calculated as 1607 / 22). Since the values are no longer 23, but now 22, the median would be the average of the 2 middlemost values, ((62+62) / 2) which would still result in 62 as the median.
d. we use the Five number summary:
Median / Interquartile Range = 62
First Quartile / Q1 = (51 +57) / 2 = 54
Third Quartile / Q3 = (99 + 104) / 2 = 101.5
Minimum = 2
Maximum = 197 ; therefore Range = (197 - 2) = 195.
Please see attached box and whisker plot. The distribution is positively skewed.
Answer
1 and 0.89
Step-by-step explanation:
idrk tho
Answer: 1999 perfect squares between 1,000,000 and 9,000,00
Step-by-step explanation:
Sq root of 1,000,000 is 1000 and square root of 9,000,000 is 3000
Hence there are squares of 1001 to 2999 I. e. 1999 perfect squares between 1,000,000 and 9,000,00
Answer:
obtuse isosceles
Step-by-step explanation:
isosceles angles
Answer:
55.734 mph
Step-by-step explanation:
Let's call the wind speed x and the time of flight t.
Then, we can write the following equation, knowing that the distance is equal speed times time of flight:
910 = (350+x) * t
660 = (350-x) * t
If we isolate t in both equations and compare its value, we have that:
910 / (350+x) = 660 / (350-x)
(350+x)/(350-x) = 910/660
350 + x = 1.3788 * (350-x)
350 + x = 482.58 - 1.3788x
2.3788x = 132.58
x = 55.734 mph