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Jobisdone [24]
3 years ago
9

The point-slope form of the equation of the line that passes through (-5, -1) and (10,-7) is

Mathematics
1 answer:
zzz [600]3 years ago
8 0

Answer:2x-5y=-15

Step-by-step explanation:

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Reyna runs a textile company that manufactures T-shirts. The profit, p, made by the company is modeled by the function
Mkey [24]

The question is incomplete:

Reyna runs a textile company that manufactures T-shirts. The profit, p, made by the company is modeled by the function p = s^2+9s-142, where s is the number of T-shirts sold. How many T-shirts should be sold to earn a profit of more than $2,000?

Answer:

s>42

Reyna needs to sell more than 42 T-shirts.

Step-by-step explanation:

Given that you have to find the amount of T-shirts that should be sold to earn a profit of more than $2,000, you have to find the amount required to earn $2,000 by replacing p with 2,000 and solving for s:

s^2+9s-142=2000

s^2+9s-2142=0

(s+\frac{9}{2})^2-2142-(\frac{9}{2})^2=0

(s+\frac{9}{2})^2=2142+(\frac{9}{2})^2

(s+\frac{9}{2})^2=2142+\frac{81}{4}

(s+\frac{9}{2})^2=\frac{8649}{4}

\sqrt{(s+\frac{9}{2})^2 } =\sqrt{\frac{8649}{4} }

s+\frac{9}{2}=\frac{93}{2}

s=\frac{93}{2}- \frac{9}{2}

s=\frac{186-18}{4}

s=\frac{168}{4}

s=42

According to this, Reyna needs to sell more than 42 T-shirts to earn a profit of more than $2,000.

8 0
3 years ago
Read 2 more answers
Are these expectations equivalent? Explain why or why not 42+35 7(6+5)<br><br> HELP PLEASE
const2013 [10]

\frac{42}{35} :\frac{6}{5}

7\left(\frac{6}{5}\right)=\frac{42}{5}

They are not equivalent.

6/5= 1.2

42/5= 8.4

3 0
3 years ago
Solve each equation 2 = e - 1
Naddik [55]

Hello!

1. 2=e-1

First, you switch sides.

e-1=2

Then, you add 1 from both sides of an equation.

e-1+1=2+1

Add by the numbers.

2+1=3

\boxed{e=3}, is the correct answer.

_____________________________________________

2. r-3=1

First, you add by 3 both sides of an equation.

r-3+3=1+3

Add by the numbers.

1+3=4

\boxed{r=4}, is the correct answer.

__________________________________________________

3. z-6.3=2.1

First, you add by 6.3 both sides of an equation.

z-6.3+6.3=2.1+6.3

Add by the numbers.

2.1+6.3=8.4

\boxed{z=8.4}, is the correct answer.

____________________________________________________

4. t-9.25=5.5

First, you add by 9.25 both sides of an equation.

t-9.25+9.25=5.45+9.25

Simplify.

=14.7

\boxed{t=14.7}, is the correct answer.

____________________________________________________

5. k-32.9=16.5

First, you add 32.9 both sides of an equation

k-32.9+32.9=16.5+32.9

Add by the numbers.

32.9+16.5=49.4

\boxed{k=49.4}, is the correct answer.

______________________________________________________

Hope this helps!

Have a nice day! :)

:D

-Charlie

Thank you!

3 0
4 years ago
Read 2 more answers
7) Staples charges $28 for 8 boxes of pencils and $47 for 4 pencil sharpeners. Ms. Felix orders 70 boxes of pencils and 21 penci
barxatty [35]

Answer:

<u><em>Ms. Felix would spend $491.75 on her order.</em></u>

Step-by-step explanation:

First, let's identify the components of this word problem that we'll need to solve it. We know that Staples charges $28 for 8 boxes of pencils, and $47 for 4 pencil sharpeners. Before we do anything else, we'll find the unit price of  the pencils and pencil sharpeners to make it easier for us. Let's begin with the boxes of pencils. 28 ÷ 8 = $3.50 per box of pencils. As for the pencil sharpeners, 47 ÷ 4 = $11.75 per sharpener. Now that we know the basic costs, let's use them to solve our problem at hand. We'll multiply the number of items ordered by the base cost of the item.

Boxes Of Pencils:

70 × $3.50= $245.00

Sharpeners:

21 × $11.75= $246.75

Now that we know the cost of the two seperate items Ms. Felix ordered, let's add them to get our final answer.

<h3>$245 + $246.75 = $491.75</h3><h3 />

Our final answer would be $491.75.

8 0
3 years ago
Express 15 x^1/3y^1/5 using a radical
k0ka [10]
In short, to convert two fractions to have the same denominator, we simply multiply one by the denominator of the other, so in this case, we'll multiply 1/3 by 5, top and bottom, and 1/5 by 3, top and bottom, thus

\bf a^{\frac{ n}{ m}} \implies  \sqrt[ m]{a^ n} &#10;\qquad \qquad&#10;\sqrt[ m]{a^ n}\implies a^{\frac{ n}{ m}}\\\\&#10;-------------------------------

\bf \cfrac{15x^{\frac{1}{3}}}{y^{\frac{1}{5}}}\qquad &#10;\begin{cases}&#10;\frac{1}{3}=\frac{1\cdot 5}{3\cdot 5}\\&#10;\qquad \frac{5}{15}\\\\&#10;\frac{1}{5}=\frac{1\cdot 3}{5\cdot 3}\\&#10;\qquad \frac{3}{15}&#10;\end{cases}\implies \cfrac{15x^{\frac{5}{15}}}{y^{\frac{3}{15}}}\implies 15\cdot \cfrac{x^{\frac{5}{15}}}{y^{\frac{3}{15}}}\implies 15\cdot \cfrac{\sqrt[15]{x^5}}{\sqrt[15]{y^3}}&#10;\\\\\\&#10;15\sqrt[15]{\frac{x^5}{y^3}}
4 0
3 years ago
Read 2 more answers
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