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-BARSIC- [3]
3 years ago
6

Ariel is putting together lunch bags for 12 students going on a field trip. She put 5 apple slices and 6 orange slices into each

bag. How many apple slices and orange slices does Ariel need?
Mathematics
2 answers:
34kurt3 years ago
8 0
12 bags x 5 apple slices = 60 apple slices
12 bags x 6 orange slices = 72 orange slices
60 apple slices and 72 orange slices
Orlov [11]3 years ago
6 0
<span>Calculate how many pieces of fruit go into each bag. Add this to the number of students going on the trip.</span>
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ANSWERRRR QUICKKKK PLEASEEEE
Brums [2.3K]

Answer: sqrt(2)/2  which is choice D

======================================================

Explanation

(3pi/4) radians converts to 135 degrees after multiplying by the conversion factor (180/pi).

The angle 135 degrees is in quadrant 2. We subtract the angle 135 from 180 to find the reference angle

180-135 = 45

Then you can use a 45-45-90 triangle to determine that the ratio of opposite over hypotenuse is sqrt(2)/2

sine is positive in quadrant 2

------------

Alternatively, you can use a unit circle. Refer to the diagram below. In red, I've circled the angle 3pi/4 radians. The terminal point for this angle has a y coordinate of sqrt(2)/2

Recall that y = sin(theta).

6 0
3 years ago
[Help Asap, Will Mark Brainliest] Answer is in the image,
Vera_Pavlovna [14]
Z=118 as vertically opposite angles are the same

x= (8x-50)
3 0
3 years ago
Read 2 more answers
Suppose that the Celsius temperature at the point (x, y) in the xy-plane is T(x, y) = x sin 2y and that distance in the xy-plane
liraira [26]

Missing information:

How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

P = (\frac{1}{2}, \frac{\sqrt 3}{2})

Answer:

Rate = 0.935042^\circ /cm

Step-by-step explanation:

Given

P = (\frac{1}{2}, \frac{\sqrt 3}{2})

T(x,y) =x\sin2y

r = 1m

v = 2m/s

Express the given point P as a unit tangent vector:

P = (\frac{1}{2}, \frac{\sqrt 3}{2})

u = \frac{\sqrt 3}{2}i - \frac{1}{2}j

Next, find the gradient of P and T using: \triangle T = \nabla T * u

Where

\nabla T|_{(\frac{1}{2}, \frac{\sqrt 3}{2})}  = (sin \sqrt 3)i + (cos \sqrt 3)j

So: the gradient becomes:

\triangle T = \nabla T * u

\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] *  [\frac{\sqrt 3}{2}i - \frac{1}{2}j]

By vector multiplication, we have:

\triangle T = (sin \sqrt 3)*  \frac{\sqrt 3}{2} - (cos \sqrt 3)  \frac{1}{2}

\triangle T = 0.9870 * 0.8660 - (-0.1606 * 0.5)

\triangle T = 0.9870 * 0.8660 +0.1606 * 0.5

\triangle T = 0.935042

Hence, the rate is:

Rate = \triangle T = 0.935042^\circ /cm

3 0
2 years ago
What's the reciprocal of 2 4/7 ?​
Gnom [1K]

Answer:

7/18

Step-by-step explanation:

²\frac{4}{7}=((2*7)+4)/7

2*7=14

14+4=18

18/7⇒7/18

4 0
3 years ago
The price of a certain computer stock t days after it is issued for sale is p(t)=100+20t−6t^2 dollars. The price of the stock in
Elanso [62]

Answer:

0 < t < \frac{5}{3}

After 1.67 days the stocks would be sold out.

Step-by-step explanation:

The price of a certain computer stock after t days is modeled by

p(t) = 100 + 20t - 6t²

Now we will take the derivative of the given function and equate it to zero to find the critical points,

p'(t) = 20 - 12t = 0

t = \frac{20}{12}

t = \frac{5}{3} days

Therefore, there are two intervals in which the given function is defined

(0, \frac{5}{3}) and (\frac{5}{3}, ∞)

For the interval (0, \frac{5}{3}),

p'(1) = 20 - 12(1) = 20

For the interval (\frac{5}{3}, ∞),

p'(2) = 20 - 12(2) = -4

Positive value of p'(t) in the interval (0, \frac{5}{3}) indicates that the function is increasing.

0 < t < \frac{5}{3}

Since at the point t = 1.67 days curve is showing the maximum, so the stocks should be sold after 1.67 days.

7 0
3 years ago
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