Question

for the school play, the advance tickets cost $3, while tickets at the door cost $5. Thirty more tickets were sold at the door than in advance, and $2630 was collected. How many of each kind of ticket was sold?​

Answer 1

310 advance tickets and 340 other tickets

Answer 2

Answer:

310 advance tickets were sold and 340 at the door tickets were sold.

Step-by-step explanation:

You know that thirty more tickets were sold at the door than in advance so we can find out how much that costs first.

More tickets sold = 30 × $5

                             = $150

Remaining tickets = $2630 - $150

                              = $2480

Now that you have deducted the extra tickets, $2480 is the sum of the tickets where the number of advance and at the door tickets are the same. You could find how much one "set" costs before finding the number of sets there are.

One set = $3 + $5

             = $8

No. of sets = $2480 ÷ $8

                  = 310

Advance tickets = 310

At the door tickets = 310 + 30

                               = 340