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Karolina [17]
3 years ago
14

for the school play, the advance tickets cost $3, while tickets at the door cost $5. Thirty more tickets were sold at the door t

han in advance, and $2630 was collected. How many of each kind of ticket was sold?​
Mathematics
2 answers:
bixtya [17]3 years ago
8 0
310 advance tickets and 340 other tickets
posledela3 years ago
8 0

Answer:

310 advance tickets were sold and 340 at the door tickets were sold.

Step-by-step explanation:

You know that thirty more tickets were sold at the door than in advance so we can find out how much that costs first.

More tickets sold = 30 × $5

                             = $150

Remaining tickets = $2630 - $150

                              = $2480

Now that you have deducted the extra tickets, $2480 is the sum of the tickets where the number of advance and at the door tickets are the same. You could find how much one "set" costs before finding the number of sets there are.

One set = $3 + $5

             = $8

No. of sets = $2480 ÷ $8

                  = 310

Advance tickets = 310

At the door tickets = 310 + 30

                               = 340

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Answer:

7 \frac{2}{3}=\frac{7*3+2}{3}=\frac{23}{3}

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3 years ago
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Answer:

8626

Step-by-step explanation:

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2 years ago
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3 0
3 years ago
Find the mean and variance of the following data<br><br> 52,34,64,49,55,26,38,63
BlackZzzverrR [31]

Answer:

Mean = 47,625

Variance, ignoring the commas = 157

Explanation:

The mean is quite simple: is the mid value of an amount (m') of numbers.

Examples:

Mean of 2, 4:  2 + 4/2 = 3

Mean of 5, 6 and 8: 1+6+8/3 = 15/3 = 5

Generalizing: M' = An + Bn-1 + Cn-2 +... + Y1/ n

So, for the enunciated, we have:

M = 52 + 34 + 64 + 49 + 55 + 26 + 38 + 63/8

M = 47,625

Variance is quite harder.

The mathematics definition is also quite harder:

∑n, i=1 (Xi - X')²/n

Traduction: the sum of the difference of the square of the dispersion measures by the arithmetic mean of them, divided by the number of observed terms is the square of the standard deviation, that is, the variance.

Don't worry, you don't need to understand that. I'll do the question, then you will see in practice what that means.

First, we need the mean of the observerd terms. We already have done that.

M = 47,625.

Next, we will do the the difference o<em>f the square </em>of the dispersion measures by the arithmetic mean of them. Which are:

A.52 - 47,625 = (4,375)²

B.34 - 47,625 = (-13,625)² - <em>Because of a value like that, you know see why</em>

C.64 - 47,625 = (16,375)²

D.49 - 47,625 = (1,375)²

E.55 - 47,625 = (7,375)²

F.26 - 47,625 = (-21,625)² - <em>we need to square everything: because a negati</em>

G.38 - 47,625 = (-9,625)² - <em>ve result doest not help in the statisc.</em>

K.63 - 47,625 = (15,375)²

I am using a calculator, but really with that, I'll aproximately the values. If you need a accurate measure, just square them all the way.

A = 16     D  = 1     G = 100

B = 169    E = 49    K = 225

C = 256   F = 441

The last part is the sum of the difference of the square of the dispersion measures by the arithmetic mean of them, dividing them by the number of observations.

16 + 169 + 256 + 1 + 49 + 441 + 100 + 225/ 8 = 157,125

8 is the number of observations.

___________________________

But why we do the variance? The variance serves to us for know how much the mean is precise.

So, the lower is the variance, the better is the mean.

Take a look on this example:

Imagine three persons, A, B and C.

They are in pub, talking about how much they receive. A gets, per month, 1000US$, b 2000 and C 3000US$.

So, their mean are 3000US$.

Now imagine that Bill Gates joins the group. And Bill, last month, got 100 milion US$.

Now the mean will be almost 25 milions of dollars.  So, she is VERY far from the reality of the major part of the group. And is in there that cames the variance. Looking to the variance, we will see that there is a big discrepancy for each observed term.

5 0
3 years ago
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