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forsale [732]
3 years ago
14

Please help will give brainliest

Mathematics
1 answer:
notka56 [123]3 years ago
3 0

Answer:

b

the points make a sad face on the graph  and if you do the vertical line test you can see that its a function

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Which of the following rational functions is graphed below?
nata0808 [166]

Answer:

B

Step-by-step explanation:

The function's zeroes results in vertical asymptotes. As one is at x = 1 and the other at x = -2, the zeroes must be (x-1) and (x+2), which only B contains in the numerator.

5 0
3 years ago
8x - 3y &lt; 4<br> 9.x + 2y &lt;-1<br> is (5, -5) a solution of the system?
mariarad [96]

Answer: 4x − 2y = 6 . . . . . (1)

2x + y = 5 . . . . . (2)

(2) x 2 => 4x + 2y = 10 . . . . . (3)

(1) - (3) gives: -4y = -4

y = -4/-4 = 1

From (2), 2x + 1 = 5 => 2x = 5 -1 = 4

x = 4/2 = 2

Solution is (2, 1)

Substituting the solution into the options gives that

−4x − 2y = 10

−4y = 4 −4x

has the same solution.

hope this helped!! :)

4 0
3 years ago
Read 2 more answers
Find the value of expression:15/3+(7-3)^2
irina1246 [14]

Answer:

21

Step-by-step explanation:

5 0
3 years ago
The perimeter of the base of a right square pyramid is 32 cm.
Serga [27]

Answer:

  170.67 cm^3

Step-by-step explanation:

The volume is given by ...

  V = 1/3s²h

We are given that 4s=32, so s=8. We are also given that h=8. (All linear dimensions are in centimeters.) Then the volume is ...

  V = (1/3)(8²)(8) = 512/3 = 170.67 . . . . cm³

_____

We have to assume that the given answer choices include a typo.

3 0
3 years ago
Please explain this problem!!!​
9966 [12]

tis a little of plain differentiation.

we know the radius of the cone is decreasing at 10 mtr/mins, or namely dr/dt = -10, decreasing, meaning is negative.

we know the volume is decreasing at a rate of 1346 mtr/mins or namely dV/dt = -1346, also negative.

so, when h = 9 and V = 307, what is dh/dt in essence.

we'll be needing the "r" value at that instant, so let's get it

V=\cfrac{1}{3}\pi r^2 h\implies 307=\cfrac{\pi }{3}r^2(9)\implies \sqrt{\cfrac{307}{3\pi }}=r

now let's get the derivative of the volume of the cone

V=\cfrac{1}{3}\pi r^2 h\implies \cfrac{dV}{dt}=\cfrac{\pi }{3}\stackrel{product~rule}{ \left[ \underset{chain~rule}{2r\cdot \cfrac{dr}{dt}}\cdot h+r^2\cdot \cfrac{dh}{dt} \right]} \\\\\\ -1346=\cfrac{\pi }{3}\left[2\sqrt{\cfrac{307}{3\pi }}(-10)(9)~~+ ~~ \cfrac{307}{3\pi } \cdot \cfrac{dh}{dt}\right]

-\cfrac{4038}{\pi }=-\cfrac{180\sqrt{307}}{\sqrt{3\pi }}+\cfrac{307}{3\pi } \cdot \cfrac{dh}{dt}\implies \left[ -\cfrac{4038}{\pi }+\cfrac{180\sqrt{307}}{\sqrt{3\pi }} \right]\cfrac{3\pi }{307}=\cfrac{dh}{dt} \\\\\\ -\cfrac{12114}{307}+\cfrac{180\sqrt{3\pi }}{\sqrt{307}}=\cfrac{dh}{dt}\implies -7.920939735970634 \approx \cfrac{dh}{dt}

5 0
2 years ago
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