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zzz [600]
3 years ago
14

For two weeks, Mark recorded the color of the traffic light at the intersection of Acorn Street and Fifth Avenue as his bus appr

oached the intersection. He created this frequency table. How many times was the traffic light red?
Red: ?
Green: 6
Yellow: 2
Total: 15
Mathematics
1 answer:
rewona [7]3 years ago
6 0
Hey there!

If the total amount of times Mark recorded the color of the traffic light is 15, then the number of red lights he recorded would be 15 minus the amount of green and yellow lights. 

15 – 6 – 2 = 7

There was a total of 7 red lights recorded by Mark. 

Hope this helped you out! :-)
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Answer:

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Step-by-step explanation:

Given

The attached graph

Required

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(x,y) = (1,40)

This means that:

x = 1\ and\ y = 40

k = \dfrac{y}{x} becomes

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mihalych1998 [28]

Answer:

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Hence the formula f(x)=-\frac{2}{3}(6)^{x-1} for x=1,2,3,... represents the given geometric sequence

Step-by-step explanation:

Given sequence is -\frac{2}{3} ,-4 ,-24 ,-144 ,...

To find the formula to describe the given sequence :

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r=6

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=\frac{-24}{-4}

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Therefore the common ratio is 6

Therefore the given sequence is geometric sequence

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a_n=a_1r^{n-1}

The formula which describes the given geometric sequence is

f(x)=a_1r^{x-1} for x=1,2,3,...

=\frac{-2}{3}6^{x-1} for x=1,2,3,...

Now verify that f(x)=a_1r^{x-1} for x=1,2,3,... represents the given geometric sequence or not

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we get f(1)=-\frac{2}{3}(6)^{1-1}

=-\frac{2}{3}(6)^0

=-\frac{2}{3}

Therefore f(1)=-\frac{2}{3}

put x=2 we get f(2)=-\frac{2}{3}(6)^{2-1}

=-\frac{2}{3}(6)^1

=-\frac{12}{3}

Therefore f(2)=-4

put x=3 we get f(3)=-\frac{2}{3}(6)^{3-1}

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Therefore f(3)=-24

Therefore the sequence is f(1),f(2),f(3),...

Therefore  the sequence is -\frac{2}{3} ,-4 ,-24 ,-144 ,...

Hence the formula f(x)=a_1r^{x-1} for x=1,2,3,... represents the given geometric sequence is verified

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