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Otrada [13]
2 years ago
9

Differentiate y=a/x+b with respect to x, when a and b are constant​

Mathematics
1 answer:
Basile [38]2 years ago
7 0

Answer:

-a/(x+b)²

Step-by-step explanation:

Given the function y = a/x+b

To differentiate, we will use the quotient rule.

dy/dx = (Vdu/dx-Udv/dx)/V²

Let u   = a

v = x+b

Note that differential of a constant is zero

du/dx = 0

dv/dx = 1

Substitute

dy/dx = (x+b)0 - a (1)/(x+b)²

dy/dx = 0 - a/(x+b)²

dy/dx = -a/(x+b)²

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Step-by-step explanation:

This is an exponential increase. As represented in the picture, approximately 77 lilly pads will be produced after 50 days when there is initial of 22.

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A circle is drawn within a square as shown.
Vinil7 [7]
<h3>Area of shaded region is 21.5 square centimeter</h3>

<em><u>Solution:</u></em>

The area of the shaded region is equal to the area of the square minus the area of the circle

<em><u> Find the area of the square</u></em>

Area\ of\ square = a^2

Where, "a" is the length of each side

From given figure in question,

a = 10 cm

Area\ of\ square = 10^2\\\\Area\ of\ square = 100\ cm^2

<em><u>Find the area of circle </u></em>

The area of the circle is given as:

Area\ of\ circle = \pi r^2

Where, "r" is the radius of circle

Diameter = 10 cm

r = \frac{diameter}{2}\\\\r = \frac{10}{2}\\\\r = 5

Thus,

Area\ of\ circle = 3.14 \times 5^2\\\\Area\ of\ circle = 3.14 \times 25\\\\Area\ of\ circle = 78.5\ cm^2

<em><u>Find the area of the shaded region</u></em>

Area of shaded Region = Area of Square - Area of Circle

Area of shaded Region = 100 - 78.5 = 21.5

Thus area of shaded region is 21.5 square centimeter

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2 years ago
You purchase 5 sliders and an order of French fries for $9.25. If fries cost $2, what is the cost of a single slide
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The graph shows the distance a car traveled, y, in x hours:
meriva

Answer:

The correct answer is 30

Step-by-step explanation:

Given: The x-axis represents the time in hours and the y-axis represents the distance in miles.

The line passes through the points (2,60) and (4,120)

To find: The rise-over-run value for the relationship in the graph.

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Thus, the rise-over-run value for the relationship represented in the graph is 30.

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