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2 years ago

Differentiate y=a/x+b with respect to x, when a and b are constant

Mathematics

1 answer:

Basile [38]2 years ago

7 0

Answer:

-a/(x+b)²

Step-by-step explanation:

Given the function y = a/x+b

To differentiate, we will use the quotient rule.

dy/dx = (Vdu/dx-Udv/dx)/V²

Let u = a

v = x+b

Note that differential of a constant is zero

du/dx = 0

dv/dx = 1

Substitute

dy/dx = (x+b)0 - a (1)/(x+b)²

dy/dx = 0 - a/(x+b)²

dy/dx = -a/(x+b)²

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For this case we must find

$(f + g) (x).$

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We have the following functions:

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$(f + g) (x) = 5x ^ 3-2 + 2x + 1\\(f + g) (x) = 5x ^ 3 + 2x-1$

Answer:

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3 years ago

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3 years ago

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Remember: We have to work from either the LHS or the RHS.
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3 years ago

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faltersainse [42]

Problem 11

<h3>Answer: h = 2A/b</h3>

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Explanation:

We need to get h by itself. To do so, we first multiply both sides by 2. Then we divide both sides by b

A = (1/2)*b*h

2A = b*h

b*h = 2A

h = 2A/b

================================================

Problem 12

<h3>Answers:</h3>

Equation: (n+2)/5 = 14
Solution to that equation: n = 68

------------------

Explanation:

The number n is increased by 2 to get n+2

Then we divide by 5 to get (n+2)/5

This is set equal to 14 to get the equation (n+2)/5 = 14

Solving the equation would look like this

(n+2)/5 = 14

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================================================

Problem 13

<h3>Answer: Not a solution</h3>

------------------

Explanation:

We'll replace every copy of x with -3 and simplify

-2x + 5 > 13

-2*(-3) + 5 > 13

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The last inequality is false because 11 is not greater than 13. Since the last inequality is false, this makes the first inequality false when x = -3.

Therefore, x = -3 is not a solution.

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Answer:

Step-by-step explanation:

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Differentiate y=a/x+b with respect to x, when a and b are constant​

Differentiate y=a/x+b with respect to x, when a and b are constant