All categories

3 years ago

Solve for x: 4(x + 4) = 6(x - 2) O A. x = 9 B. x = 14 O C. x = 8 D. x = 1

Mathematics

2 answers:

ad-work [718]3 years ago

5 0

Answer: 14 = x

Step-by-step explanation: Start by distributing through the parenthses

on each side of the equation to get 4x + 16 = 6x - 12.

Now move your x's to the right and numbers

to the left and you get 28 = 2x.

Divide both sides by 2 and 14 = x.

BigorU [14]3 years ago

4 0

Answer:

x = 14

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Equality Properties

Step-by-step explanation:

Step 1: Define equation

4(x + 4) = 6(x - 2)

Step 2: Solve for x

Distribute: 4x + 16 = 6x - 12
Subtract 4x on both sides: 16 = 2x - 12
Add 12 on both sides: 28 = 2x
Divide 2 on both sides: 14 = x
Rewrite: x = 14

Step 3: Check

Plug in x to verify it's a solution.

Substitute: 4(14 + 4) = 6(14 - 2)
Add/Subtract: 4(18) = 6(12)
Multiply: 72 = 72

And we have our final answer!

You might be interested in

One cube has a volume of 192 cm3, and another has a volume of 375 cm3. How much longer is the edge of the larger cube than that

vesna_86 [32]

Answer:

134

Step-by-step explanation:

5 0

3 years ago

What is the slope of this line

Elenna [48]

Answer:

Step-by-step explanation:

rise/run = slope

As it goes to the left or adds by one, it goes up by 4

4/1

3 0

3 years ago

Read 2 more answers

Chose all the values of x that are not in the domain of this rational function. Picture attached, 15 points and I'll give Brainl

pogonyaev

Answer:

All of them.

Step-by-step explanation:

For rational functions, the domain is all real numbers except for the zeros of the denominator.

Therefore, to find the x-values that are not in the domain, we need to solve for the zeros of the denominator. Therefore, set the denominator to zero:

$x(x-1)(x^2-4)=0$

Zero Product Property:

$x\neq 0\text{ or }x-1\neq 0\text{ or }x^2-4\neq 0$

Solve for the x in each of the three equations. The first one is already solved. Thus:

$x-1\neq 0 \text{ or }x^2-4\neq 0\\x\neq 1\text{ or }x^2\neq 4\\x\neq 1 \text{ or }x\neq\pm 2$

Thus, the values that cannot be in the domain of the rational function is:

$x=-2,0,1,2$

Click all the options.

6 0

3 years ago

Read 2 more answers

please help me Which of the following choices will evaluate the function ƒ(x) = -(-x), when x = -3? 3 -1 -3 None of these choice

Vadim26 [7]

Answer:

-3

Step-by-step explanation:

Given the function f(x) = -(-x)

we want to evaluate f(-3)

What we do simply here is substitute the value of -3 for x in the equation

That would be ;

f(-3) = -(-(-3)) = -(3) = -3

8 0

3 years ago

Need help factoring this binomial: x^4-1?

natima [27]

Use the difference of squares factorization - that for any numbers a and b, (a-b)(a+b)=a^2-b^2.

We have:

(x^2+1)(x^2-1)=x^4-1

In addition:

(x-1)(x+1)=x^2-1, so we have:

(x^2+1)(x+1)(x-1)

As our complete factorization.

5 0

3 years ago

Read 2 more answers