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vodka [1.7K]
3 years ago
10

Solve the following equation : 7x/15-1=22

Mathematics
2 answers:
miskamm [114]3 years ago
6 0
\frac{7x}{15-1} =22
-----------------
To solve this all it takes is two simple steps
Simplify \frac{7x}{15-1} =22
1/2x =22
------------------------
Multiply both sides by 2
2 · \frac{1}{2} = 2 · 22
x = 44
Semenov [28]3 years ago
5 0
Hey there Smarty!

\boxed{\boxed{Rearrange \ the \ equation \ by \ subtracting}}

\left[\begin{array}{ccc}\boxed{\boxed{ 7*x/15-1-(22)=0 }}\end{array}\right]

\boxed{((7* \frac{x}{15)}-1)-22=0}}

\left[\begin{array}{ccc} \frac{(7x - 15)  }{15} -22=0\end{array}\right]

Add \  345 \  to \ both \ sides \ of \ the \ equation : \\ \\
                      7x = 345 \\ \\ Divide \ both \ sides \ of \ the \ equation \  by \ 7:
                     x = 345/7 = \boxed{\boxed{49.28}}




Hope this helps you!
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Division was used in the first example.
VLD [36.1K]
Ok




Sulition because I said do
4 0
3 years ago
13. f(x) = x^4<br> - 9x2 -22x - 24
Anna007 [38]

Answer:

x = 4 or x = -2

Step-by-step explanation:

Solve for x over the real numbers:

x^4 - 9 x^2 - 22 x - 24 = 0

The left hand side factors into a product with three terms:

(x - 4) (x + 2) (x^2 + 2 x + 3) = 0

Split into three equations:

x - 4 = 0 or x + 2 = 0 or x^2 + 2 x + 3 = 0

Add 4 to both sides:

x = 4 or x + 2 = 0 or x^2 + 2 x + 3 = 0

Subtract 2 from both sides:

x = 4 or x = -2 or x^2 + 2 x + 3 = 0

Subtract 3 from both sides:

x = 4 or x = -2 or x^2 + 2 x = -3

Add 1 to both sides:

x = 4 or x = -2 or x^2 + 2 x + 1 = -2

Write the left hand side as a square:

x = 4 or x = -2 or (x + 1)^2 = -2

(x + 1)^2 = -2 has no solution since for all x on the real line, (x + 1)^2 >=0 and -2<0:

Answer:  x = 4 or x = -2

3 0
3 years ago
Find the area of a rectangle with side lengths 5/8 ft and 1/3 ft.
forsale [732]

Answer:

\frac{5}{24} ft^{2}

Step-by-step explanation:

\frac{5}{24} ft^{2}

5 0
3 years ago
what is the experimental probability of the spinner of it landing on blue? if it has green in the upper left corner, blue in the
Sidana [21]
1/4 are you chances in that question
7 0
3 years ago
When testing a claim that the majority of adult Americans are against the death penalty for a person convicted of murder, a rand
Black_prince [1.1K]

Using the z-distribution, it is found that the p-value is of 1.

At the null hypothesis, it is tested <u>that the majority is not against the death penalty</u>, that is:

H_0: p \neq 0.5

At the alternative hypothesis, it is <u>tested that the majority is against the death penalty</u>, that is:

H_1: p > 0.5

The test statistic is given by:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}

In which:

  • \overline{p} is the sample proportion.
  • p is the proportion tested at the null hypothesis.
  • n is the sample size.

In this problem, the parameters are: \overline{p} = 0.27, p = 0.5, n = 491.

Then, the value of the <em>test statistic</em> is:

z = \frac{\overline{p} - p}{\sqrt{\frac{p(1-p)}{n}}}

z = \frac{0.27 - 0.5}{\sqrt{\frac{0.5(0.5)}{491}}}

z = -10.19

Using a z-distribution calculator, for a <u>right-tailed test</u>, as we are testing if the proportion is greater than a value, the p-value is of 1.

A similar problem is given at brainly.com/question/16313918

3 0
3 years ago
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