Answer:
H2CO3,HCl
Explanation:
the rest are not acids but I arrange the acids based on their number of hydrogen
Answer:
The correct answer would be = 0.1593 mCi.
Explanation:
The initial 123I = 2.55 mCi (given)
We know that the half-life of radioactive I-123 = 12 hours approximately.
So, we can say that in 48 hours there will be four half-lives of 123I,
Hence after four half-life or 48 hours, the final 123I would be:
= 2.55 * (1/2⁴)
= 2.55 * (1/16)
= 0.1593 mCi
Thus, the correct answer would be = 0.1593 mCi.
Answer: No hydrogen bond cannot occur in this alpha helix structure.
Explanation: For hydrogen bond to form, the electronegativity difference should be more than 1.7. carbon has an electronegativity of 2.5 whereas hydrogen has 2.1 so their electronegativity difference is 0.3. So in this alpha helix structure cannot occur.
Answer:
2,93x10³atmL, 2,97x10⁵J
Explanation:
The work done in gas compression under constant pressure is:
W = -P×ΔV
<em>Where W is work done, P is pressure and </em>ΔV <em>is change in volume (Vol.f - Vol.i)</em>
Replacing:
W = -61.0atm×(51.0L - 99.0L)
W = 2928atmL = <em>2,93x10³atmL</em>
In Joules:
2928atmL × (101,325J / 1atmL) = 296680J ≡<em> 2,97x10⁵J</em>
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I hope it helps!
I would say D. Let me know if i am wrong.