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mr Goodwill [35]
4 years ago
12

How does things go sublime

Chemistry
1 answer:
Lemur [1.5K]4 years ago
5 0
Things go sublime when changing automatically into vapor when it is heated, usually forming a solid figure.
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What are the uses of polythene?
Crank
Polyethylene is synthesized from ethylene which is a compound derived from natural gas or petroleum. It’s essentially a thermoplastic, implying that it can be molten and remolded into the desired shape making it reusable and cost-effective. Of all the different kinds of plastics produced around the world, polyethylene is the most common and significant.

Polyethylene is manufactured in three different forms namely:

Low Density Polyethylene (LDPE),High Density Polyethylene (HDPE) andLinear Low Density Polyethylene (LLDPE),

Each of these three plastics has different applications ranging from containers, packaging and films to buckets and bottles.

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7 0
3 years ago
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An analytical chemist is titrating of a solution of propionic acid with a solution of 224.9 ml of a 0.6100M solution of propioni
Svetllana [295]

<u>Answer:</u> The pH of acid solution is 4.58

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}    .....(1)

  • <u>For KOH:</u>

Molarity of KOH solution = 1.1000 M

Volume of solution = 41.04 mL

Putting values in equation 1, we get:

1.1000M=\frac{\text{Moles of KOH}\times 1000}{41.04}\\\\\text{Moles of KOH}=\frac{1.1000\times 41.04}{1000}=0.04514mol

  • <u>For propanoic acid:</u>

Molarity of propanoic acid solution = 0.6100 M

Volume of solution = 224.9 mL

Putting values in equation 1, we get:

0.6100M=\frac{\text{Moles of propanoic acid}\times 1000}{224.9}\\\\\text{Moles of propanoic acid}=\frac{0.6100\times 224.9}{1000}=0.1372mol

The chemical reaction for propanoic acid and KOH follows the equation:

                 C_2H_5COOH+KOH\rightarrow C_2H_5COOK+H_2O

<u>Initial:</u>          0.1372         0.04514  

<u>Final:</u>           0.09206          -                0.04514

Total volume of solution = [224.9 + 41.04] mL = 265.94 mL = 0.26594 L     (Conversion factor:  1 L = 1000 mL)

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a+\log(\frac{[\text{salt}]}{[acid]})

pH=pK_a+\log(\frac{[C_2H_5COOK]}{[C_2H_5COOH]})

We are given:  

pK_a = negative logarithm of acid dissociation constant of propanoic acid = 4.89

[C_2H_5COOK]=\frac{0.04514}{0.26594}

[C_2H_5COOH]=\frac{0.09206}{0.26594}

pH = ?  

Putting values in above equation, we get:

pH=4.89+\log(\frac{(0.04514/0.26594)}{(0.09206/0.26594)})\\\\pH=4.58

Hence, the pH of acid solution is 4.58

7 0
4 years ago
Calculate the volume in mL of a 0.708 M KOH solution containing 0.098 mol of solute
Olenka [21]
Molarity = mol/liter

0.708M = 0.098mol/L
Rearrange to find L:
0.098mol/0.708M = .138L

For every liter there is 1000 mL:
.138L • 1000mL =138mL KOH
7 0
4 years ago
Where in a data table should units of measurement be shown?
Vikentia [17]
The unites of measurement in a data table should be shown in the headings of some columns.
6 0
4 years ago
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The formation of a gas or a precipitate may be evidence for a ___________.
ololo11 [35]
Reaction [taking place]

Hope that helps
5 0
3 years ago
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