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3 years ago

You took 600mg of pain reliever at

Mathematics

1 answer:

Ber [7]3 years ago

4 0

Answer:

It’s not a question for studying

Step-by-step explanation:

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How do I get (tan^2(x)-sin^2(x))/tan(x) equal to (sin^2(x))/cot(x)

shepuryov [24]

$LHS\\ \\ =\frac { \tan ^{ 2 }{ x-\sin ^{ 2 }{ x } } }{ \tan { x } } \\ \\ =\frac { 1 }{ \tan { x } } \left( \tan ^{ 2 }{ x-\sin ^{ 2 }{ x } } \right)$

$\\ \\ =\frac { \cos { x } }{ \sin { x } } \left( \frac { \sin ^{ 2 }{ x } }{ \cos ^{ 2 }{ x } } -\frac { \sin ^{ 2 }{ x\cos ^{ 2 }{ x } } }{ \cos ^{ 2 }{ x } } \right) \\ \\ =\frac { \cos { x } }{ \sin { x } } \left( \frac { \sin ^{ 2 }{ x-\sin ^{ 2 }{ x\cos ^{ 2 }{ x } } } }{ \cos ^{ 2 }{ x } } \right)$

$\\ \\ =\frac { \cos { x } }{ \sin { x } } \cdot \frac { \sin ^{ 2 }{ x\left( 1-\cos ^{ 2 }{ x } \right) } }{ \cos ^{ 2 }{ x } } \\ \\ =\frac { \cos { x } }{ \sin { x } } \cdot \frac { \sin ^{ 2 }{ x\cdot \sin ^{ 2 }{ x } } }{ \cos ^{ 2 }{ x } } \\ \\ =\frac { \cos { x } \sin ^{ 4 }{ x } }{ \sin { x\cos ^{ 2 }{ x } } } \\ \\ =\frac { \sin ^{ 3 }{ x } }{ \cos { x } }$

$\\ \\ =\sin ^{ 2 }{ x } \cdot \frac { \sin { x } }{ \cos { x } } \\ \\ =\sin ^{ 2 }{ x } \cdot \frac { 1 }{ \frac { \cos { x } }{ \sin { x } } } \\ \\ =\sin ^{ 2 }{ x } \cdot \frac { 1 }{ \cot { x } } \\ \\ =\frac { \sin ^{ 2 }{ x } }{ \cot { x } } \\ \\ =RHS$

8 0

3 years ago

A book has a front and a back and 400 pages. The front and back cover are each 0.9mm thick measured to 1 decimal place. Each pag

zhuklara [117]

The minimum thickness of the book would simply be the sum of the thickness of the two cover pages and all the pages in between. That is:

minimum thickness = 0.9 mm * 2 + 0.13 mm * 400

minimum thickness = 53.8 mm

3 0

3 years ago

The graph of the function f(x) = (x − 3)(x + 1) is shown.

Travka [436]

Answer:

Real values of x where x < -1

Step-by-step explanation:

Above the x-axis, the function is positive.

The function is decreasing when the gradient is negative.

The function has a positive

${x}^{2}$

coefficient, therefore the vertex is a local minimum;

This means the gradients are negative before the vertex and positive after it;

To meet the conditions therefore, the function must be before the vertex and above the x-axis;

This will be anywhere before the x-intercept at x = -1;

Hence it is when x < -1.

8 0

3 years ago

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Find the value of 6x+8 and 4x+2 that will make L||M Please Help

Mariana [72]

Answer:

Step-by-step explanation:

6x+8=4x+2

2x=-6

x=-3

they both are -10=-10

7 0

3 years ago

Solve for T: R = X - T please help Me!!

777dan777 [17]

The answer to the question

3 0

3 years ago