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RoseWind [281]
3 years ago
11

Rea Calculations

Mathematics
1 answer:
son4ous [18]3 years ago
7 0
Area = length x width
10 X 5 = 50
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What is the height of a rectangular prism that has a volume of 280 cubic meters,a length of 8 meters, and a width of 7 meters? S
lyudmila [28]
When looking at a rectangular prism, we know that Volume = length * width * height

If we are given that the volume of the prism is 280 cubic meters (m^3), the length is 8 meters, and the width is 7 meters, we can fill in our equation.

280 = 8 * 7 * height
280 = 56 * height

Because we are solving for the height, we divide both sides by 56

280/56 = height

height = 5 meters

8 0
3 years ago
Can someone explain to me how to do this and give me the answer please?​
pantera1 [17]

Answer:

To find x, y, z, p and q, you need to know about the property of Rhombus.

13y + 10 = 7y + 16 (pair of equal opposite sides)

=> 6y = 6

=> y = 1

x = 7x + 16 (2 equal adjacent sides)

  = 7*1 + 16

  =23

z = 90 deg (angle between 2 diagonals)

q = 22 deg (isosceles triangle)

p = 90 - 22 = 68 deg (right triangle)

4 0
3 years ago
How do you solve (3/5)x+1/4=(3/4)x-2/5 for x?
sveta [45]

Answer:

(3/5)x+1/4=(3/4)x-2/5

<=> (3/5)x - (3/4)x= -2/5 - 1/4

<=> x(12/20 - 15/20) = -13/20

<=> x(-3/20) = -13/20

<=> x = 13/3

Step-by-step explanation:

5 0
3 years ago
Find the point on the plane x - y + z = 4 that is closest to the point (1, 2, 3). (give your values correct to at least two deci
vova2212 [387]

no rurio greob tryo yeu

4 0
3 years ago
The length of tile B is about 3.87298 inches. Which mark on the tape measure is closest to 3.87298 inches? The tape measure is m
vladimir1956 [14]

Answer:

\frac{62}{16}

Step-by-step explanation:

We are given that,

Length of the tile = 3.87298 inches.

The markings on the tape are marked in \frac{1}{16} inches.

As, we see that,

\frac{64}{16} = 4 inches.

So, the required mark will be before than \frac{64}{16} mark.

Since, \frac{62}{16} = 3.875

Hence, the mark closest to 3.87298 inches is \frac{62}{16}.

7 0
3 years ago
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