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Soloha48 [4]
2 years ago
6

51/68 in simplest form

Mathematics
2 answers:
Valentin [98]2 years ago
5 0

Answer:

dcmcmcmckcmckxkckckfsoxo

Step-by-step explanation:

ckckckcjckdkskskxkckds

yanalaym [24]2 years ago
3 0

Answer:3/4

Step-by-step explanation:

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How many Days 'til Christmas
Nuetrik [128]

Answer:

13 days till Christmas

6 0
3 years ago
Read 2 more answers
Which of the following sets are subspaces of R3 ?
Ratling [72]

Answer:

The following are the solution to the given points:

Step-by-step explanation:

for point A:

\to A={(x,y,z)|3x+8y-5z=2} \\\\\to  for(x_1, y_1, z_1),(x_2, y_2, z_2) \varepsilon A\\\\ a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)

                                        =3(aX_l +bX_2) + 8(ay_1 + by_2) — 5(az_1+bz_2)\\\\=a(3X_l+8y_1- 5z_1)+b (3X_2+8y_2—5z_2)\\\\=2(a+b)

The set A is not part of the subspace R^3

for point B:

\to B={(x,y,z)|-4x-9y+7z=0}\\\\\to for(x_1,y_1,z_1),(x_2, y_2, z_2) \varepsilon  B \\\\\to a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)

                                             =-4(aX_l +bX_2) -9(ay_1 + by_2) +7(az_1+bz_2)\\\\=a(-4X_l-9y_1+7z_1)+b (-4X_2-9y_2+7z_2)\\\\=0

\to a(x_1,y_1,z_1)+b(x_2, y_2, z_2) \varepsilon  B

The set B is part of the subspace R^3

for point C: \to C={(x,y,z)|x

In this, the scalar multiplication can't behold

\to for (-2,-1,2) \varepsilon  C

\to -1(-2,-1,2)= (2,1,-1) ∉ C

this inequality is not hold

The set C is not a part of the subspace R^3

for point D:

\to D={(-4,y,z)|\ y,\ z \ arbitrary \ numbers)

The scalar multiplication s is not to hold

\to for (-4, 1,2)\varepsilon  D\\\\\to  -1(-4,1,2) = (4,-1,-2) ∉ D

this is an inequality, which is not hold

The set D is not part of the subspace R^3

For point E:

\to E= {(x,0,0)}|x \ is \ arbitrary) \\\\\to for (x_1,0 ,0) ,(x_{2},0 ,0) \varepsilon E \\\\\to  a(x_1,0,0) +b(x_{2},0,0)= (ax_1+bx_2,0,0)\\

The  x_1, x_2 is the arbitrary, in which ax_1+bx_2is arbitrary  

\to a(x_1,0,0)+b(x_2,0,0) \varepsilon  E

The set E is the part of the subspace R^3

For point F:

\to F= {(-2x,-3x,-8x)}|x \ is \ arbitrary) \\\\\to for (-2x_1,-3x_1,-8x_1),(-2x_2,-3x_2,-8x_2)\varepsilon  F \\\\\to  a(-2x_1,-3x_1,-8x_1) +b(-2x_1,-3x_1,-8x_1)= (-2(ax_1+bx_2),-3(ax_1+bx_2),-8(ax_1+bx_2))

The x_1, x_2 arbitrary so, they have ax_1+bx_2 as the arbitrary \to a(-2x_1,-3x_1,-8x_1)+b(-2x_2,-3x_2,-8x_2) \varepsilon F

The set F is the subspace of R^3

5 0
3 years ago
What is the solution for the system of equations {9x+8y=3 6x−12y=−11?
lions [1.4K]

Answer:

( - \frac{1}{3}, \frac{3}{4} )

Step-by-step explanation:

Given the 2 equations

9x + 8y = 3 → (1)

6x - 12y = - 11 → (2)

To eliminate the y- term multiply (1) by 1.5

13.5x + 12y = 4.5 → (3)

Add (2) and (3) term by term

(6x + 13.5x) + (- 12y + 12y) = (- 11 + 4.5)

19.5x = - 6.5 ( divide both sides by 19.5 )

x = \frac{-6.5}{19.5} = - \frac{1}{3}

Substitute this value into either of the 2 equations and solve for y

Using (1), then

- 3 + 8y = 3 ( add 3 to both sides )

8y = 6 ( divide both sides by 8 )

y = \frac{6}{8} = \frac{3}{4}

Solution is (- \frac{1}{3}, \frac{3}{4} )

6 0
3 years ago
Someone please help out! Really need to pass :(
ValentinkaMS [17]

Answer:

ok ill help

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The ratio of dogs to cats at a local animal shelter is 13/25. Which statement must be true?
Ivan

<em>Option:</em>

<em>a. for every 13 dogs, there are 25 cats. </em>

<em>b. there are twice as many cats as dogs at the shelter. </em>

<em>c. the shelter has more dogs than cats. </em>

<em>d. there are 25 animals in the shelter.</em>

Answer:

a. for every 13 dogs, there are 25 cats.

<em></em>

Step-by-step explanation:

Represent Dogs with D and Cats with C;

So;

\frac{D}{C} = \frac{13}{25}

By comparison:

D=13

C = 25

This implies that:

For every 13 D, there are 25 C

Hence: Option A is true

6 0
2 years ago
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