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larisa [96]
3 years ago
15

Use the coordinate rule (x, y) - (x-3, y+2) to translate PQR.

Mathematics
2 answers:
den301095 [7]3 years ago
8 0
Well the rule is describing a “translation” which is just moving the line so it’s the exact same measure that just in a different place!

I hope this helped!
Kaylis [27]3 years ago
6 0

Answer:

i got B, D

Step-by-step explanation:

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María compró 78 metros de cuerda, ella dividió en 6 partes iguales la cuerda el día martes 8 de mayo ¿Cuántos metros mide cada t
barxatty [35]

Answer:

The length of each piece is 13 m.

Step-by-step explanation:

Maria bought 78 meters of rope, she divided the rope into 6 equal parts on Tuesday, May 8, How many meters is each piece?  

a) Each piece measures 312m

c) Each piece measures 13m

d) each piece mites 92m

b) Each piece measures 9m and 75cm

Total length, L =  78 m

Number of pieces, n = 6

length of each piece,

d = L/n = 78/6 = 13 m

So, the correct option is (c).  

6 0
3 years ago
Rana is traveling on an airline that give a maximum weight of 65 kg. the first bag weighs 40.​
n200080 [17]

Answer:

What's the question here?

Step-by-step explanation:

The weight of the 1st bag is independent from the airline weight specification given. If the max weight of 65kg is given, this means that she/he can take on board (including the luggage) a maximum of 65kg. Does not include human weight

6 0
2 years ago
Classify the following triangle. Check all that apply
Pavlova-9 [17]
Scalene triangle I am so sure ohhh
7 0
3 years ago
Read 2 more answers
What’s the area of polygon w
natali 33 [55]
Should be 7 cause 1×7=7
8 0
3 years ago
Evaluate the definite integral. <br> 1 x4(1 + 2x5)5 dx.
Nata [24]

Answer:

Step-by-step explanation:

Given the definite integral \int\limits {\dfrac{x^4}{(1-2x^5)^5} } \, dx, we to evaluate it. Using integration by substitution method.

Let u = 1-2x⁵ ...1

du/dx = -10x⁴

dx = du/-10x⁴.... 2

Substitute equation 1 and 2 into the integral function and evaluate the resulting integral as shown;

= \int\limits {\dfrac{x^4}{u^5} } \, \dfrac{du}{-10x^4}

= \dfrac{-1}{10} \int\limits {\dfrac{du}{u^5} }  \\\\= \dfrac{-1}{10} \int\limits {{u^{-5}du }  \\= \dfrac{-1}{10} [{\frac{u^{-5+1}}{-5+1}]  \\\\= \dfrac{-1}{10} ({\frac{u^{-4}}{-4})\\\\

= \dfrac{u^{-4}}{40} \\\\\\= \dfrac{1}{40u^4} +C

substitute u = 1-2x⁵ into the result

= \dfrac{1}{40(1-2x^5)^4} +C

Hence\int\limits {\dfrac{x^4}{(1-2x^5)^5} } \, dx = \dfrac{1}{40(1-2x^5)^4} +C

5 0
3 years ago
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