Answer:
a. 2x+3z
b. 7xy
c. 
d. 10z-6q
e. Subtract xy from the sum of p and q.
f. Divide the sum of 3 and y by 5.
g. Subtract 2c from the square root of b.
h. 3x ... 4x ...
i. 3y ... y+5 ... 5y+5
j. length ... 3 ... breadth ... 8b ... 3b²
Step-by-step explanation:
Sum means addition. 2x + 3z
Product means multiplication. 7y × x = 7xy
Divide 3ab by 2c. 3ab ÷ 2c = 
Subtract 6q from 10z. 10z-6q
(p+q)-xy
: Subtract xy from the sum of p and q.
(3+y)/5: Divide the sum of 3 and y by 5.
- 2c: Subtract 2c from the square root of b.
Let the number of boys be x. Girls are three times more so 3 × x = 3x. The total would be 3x + x = 4x.
Let Nora's age be y. Father is three times more so 3 × y = 3y. Brother is 5 more so would be y+5. The total would be y + 3y + y + 5 = 5y+5
3b is three times more than b, the breadth. Thus, the length is three times more than the breadth since it is 3b. The perimeter would be 3b + b + 3b + b = 8b. The area would be 3b × b = 3b²
Answer:
97
Step-by-step explanation:
5 * 85 - 4* 82 = 97
Answer:
A
Step-by-step explanation:
The line cuts the y at positive two. The rise over run of the slope is -3/1, or 3.
Just had a test on these kinds of problems and i got 100.
Given:
Sum of interior angle
To find:
Number of sides of a polygon
Solution:
Using sum of interior angles formula:

where "S" is the sum of interior angels and "n" is the number of sides of a polygon.
Divide by 180° on both sides.

Cancel common factor 180°.

Add 2 on both sides.


Switch the sides.

Therefore number of sides of a polygon is
.