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Fed [463]
3 years ago
15

Can someone help me please..

Mathematics
1 answer:
Elza [17]3 years ago
5 0
So just find circumference is
circumfernce=2pir or pid
so diameter 2.5 ft
just for this problem aprox pi=3.14 so
c=pid
c=3.14(2.5)
c=7.85

a. 7.85 ft

b. how many times revolution till one mile (5280)
so
7.85 times x revolutions=5280
divide both sides b y7.85
x revolutions=672.61
round up so we complete the mile (about how many times..)
673 is the answer


a. 7.85 ft
b. 673 times
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What is the product of 2•2
lisabon 2012 [21]

Answer:

4

Step-by-step explanation:

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2 rows of 2

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7 0
3 years ago
The following are the last 10 run scores Colin got in cricket: 23, 20, 4, 19, 28, 35, 25, 0, 1, 30 a) Work out Colin's mean scor
sdas [7]

Answer:

I have given it step by step below.

Step-by-step explanation:

(i) Mean = sum of observations/total no. of observation

= 23 + 20  + 4 + 19 + 28 + 35 + 25 + 0  +1 + 30/ 10

= 185/10

= 18.5

(ii) additional 35 runs

New Mean

=previous total  + 35/10 + 1     (the 1 gets added in denominator because of                                           the additional observation)

= 185 + 35/11

= 220/11

= 20

Hope this helps you!

4 0
3 years ago
If the price is increasing at a rate of 2 dollars per month when the price is 10 dollars, find the rate of change of the demand.
densk [106]

Answer:

The demand reduces by $7.12 per month

<em></em>

Step-by-step explanation:

Given

p\to price

x \to demand

2x^2+5xp+50p^2=24800.

p =10; \frac{dp}{dt} = 2

Required

Determine the rate of change of demand

We have:

2x^2+5xp+50p^2=24800.

Differentiate with respect to time

4x\frac{dx}{dt} + 5x\frac{dp}{dt} + 5p\frac{dx}{dt} + 100p\frac{dp}{dt} = 0

Collect like terms

4x\frac{dx}{dt} + 5p\frac{dx}{dt} = -5x\frac{dp}{dt}  - 100p\frac{dp}{dt}

Factorize

\frac{dx}{dt}(4x + 5p) = -5(x  + 20p)\frac{dp}{dt}

Solve for dx/dt

\frac{dx}{dt} = -\frac{5(x  + 20p)}{4x + 5p}\cdot \frac{dp}{dt}

Given that: 2x^2+5xp+50p^2=24800. and p = 10

Solve for x

2x^2 + 5x * 10 + 50 * 10^2 = 24800

2x^2 + 50x + 5000 = 24800

Equate to 0

2x^2 + 50x + 5000 - 24800 =0

2x^2 + 50x -19800 =0

Using a quadratic calculator, we have:

x \approx -113\ and\ x\approx88

Demand must be greater than 0;

So: x=88

So, we have: x=88; p =10; \frac{dp}{dt} = 2

The rate of change of demand is:

\frac{dx}{dt} = -\frac{5(88  + 20*10)}{4*88 + 5*10} * 2

\frac{dx}{dt} = -\frac{5(288)}{402} * 2

\frac{dx}{dt} = -\frac{2880}{402}

\frac{dx}{dt} \approx -7.16

<em>This implies that the demand reduces by $7.12 per month</em>

8 0
3 years ago
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antiseptic1488 [7]

Answer:

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Distribute

48 +8x = 11x

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48 = 11x-8x

48 = 3x

Divide by 3

48/3 = 3x/3

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5 0
3 years ago
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inn [45]
Given 3x+4y+2+6y+3

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The constant is 3

8 0
4 years ago
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