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Aleksandr-060686 [28]
3 years ago
11

Bart wants to rent a car. The fee is $25 plus $0.55 per mile. He has budgeted $212 for the car. Write an

Mathematics
1 answer:
Georgia [21]3 years ago
4 0

Answer:

25 + 0.55x ≤ 212

Step-by-step explanation:

Bart can only spend 212, hence the less than or equal to symbol. The cost of using the car must be at most 212, so 25 and 0.55x are on the same side. 0.55x represents the cost of driving an unknown amount of miles.

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2x+3y=12 complete the missing value in the solution to the equation
likoan [24]

Answer:

(-6,8) is your answer.

Step-by-step explanation:

1. 2x + 3y = 12

2. 2x +3 * 8 = 12

3. 2x + 24 = 12

4. 2x = -12

5. x = -6

So, our final answer is (-6,8)

6 0
4 years ago
John has a bag of different colored marbles. He has 6 red marbles, 3 blue marblos, 7 yellow marbles, and 5 green marbles. If Joh
DanielleElmas [232]

Answer:

3/21, 14.29%, or 14.29

Step-by-step explanation:

John has 21 total marbles, which includes 3 blue ones.

(That's 3 over 21)

Hope this helps!

6 0
3 years ago
Answer correctly please
Paul [167]

Answer:

\$272,49

Step-by-step explanation:

7. \displaystyle /text{The answer makes sense because since the depreciation rate is 15%, we know that we need to use the "exponential decay" formula.}

6. \displaystyle /text{After a depreciation rate of 15% for the past 8 years, the stock is now worth approximately $272,49.}

5. \displaystyle 1000[0,85]^8 = 272,490525 ≈ \$272,49

4. \displaystyle 1000 = a \\ -15\% + 100\% = 1 - r; 85\% = 1 - r \\ 8\:years = time\:[t]

3. \displaystyle /text{We need to use the "Exponential Decay" formula} - f(t) = a[1 - r]^t, where a > 0

2. \displaystyle /text{How much is the stock worth after a depreciation rate of 15% per year?}

1. \displaystyle /text{initial amount: $1000, a depreciation rate of 15%, and a time period of 8 years}

I am joyous to assist you anytime.

5 0
3 years ago
I really need help with this question
Naily [24]

Answer:

7/12.

Step-by-step explanation:

Let's go over the details.

Box A contains 3, 5, and 6, and 9. Box B contains 1, 4, and 7.

Only 1 card is picked from each box.

For the sake of simplicity, let's take a step back. Let's assume that the actual values of the cards only indicate whether they are odd or even. So, we can replace the values with O for odd and E for even.

Box A now contains O(3), O(5), E(6), O(9), and Box B now contains O(1), E(4), O(7).

From logic, we can deduce that O + O = E, E + E = E, and E + O = O.

We're only looking at the combinations that result in an even sum. So we're specifically looking for OO and EE combinations.

Now that we know what we're looking for, we can go back to original problem.

There are a total of 12 possibilities if you use the values of the cards. Therefore, there is a \frac{1}{12} chance that you will get a specific combination.

To find the probability of getting a specific combination, you need to multiply the number of cards from Box A with the number of cards in Box B. So the possible combinations would be:

(3,1), (5,1), (6,1), (9,1), (3,4), (5,4), (6,4), (9,4), (3,7), (5,7), (6,7), (9,7)

But since we're looking only for (O,O) and (E,E) combinations, we can ignore all of the (O,E) and (E,O) combinations.

(3,1), (5,1), (9,1), (6,4), (3,7), (5,7), (9,7)

These account for 7 of the 12 possible combinations.

So the probability of getting two numbers whose sum is even, or (to put it in simpler terms) the probability of getting an OO or EE combination, is \frac{7}{12}.

4 0
3 years ago
5.7 x 3.6 help me asap​
Mama L [17]

Answer:

20.52

Step-by-step explanation:

I used a calculator

6 0
3 years ago
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