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2 years ago

A sequence can be generated by using an=3an−1, where a1=7 and n is a whole number greater than 1.

Mathematics

1 answer:

siniylev [52]2 years ago

5 0

Answer:

Suppose we add up alternate Fibonacci numbers, Fn-1 + Fn+1; that is, what do ... L(1)=1 and L(3)= 4 so their sum is 5 whereas F(2)=1; L(2)=3 and L(4)= 7 so their ... What is the relationship between F(n-2), and F(n+2)? You should be able to find a ... Fib(N); K (an EVEN number!), Lucas(K) and Fib(K) in each expression like ...

Step-by-step explanation:

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−\frac{7}{10} ÷\frac{2}{5}

bazaltina [42]

$$ −\frac{7}{10} \div\frac{2}{5}= \frac{-7}{4} $$ . totally answer. I hope helping with this answer

3 0

2 years ago

What is the LCD for the problem below.<br><br><br>5/8−1/7

shepuryov [24]

Answer:

The lowest common denominator or least common denominator (abbreviated LCD) is the least common multiple of the denominators of a set of fractions. It is the smallest positive integer that is a multiple of each denominator in the set. Fractions write with fraction bar / like 3/4 .

4 0

2 years ago

A sum of $4000 is invested at 5.5% interest per year. Find the amount of time needed to double the money if it’s compounded mont

musickatia [10]

9514 1404 393

Answer:

C) 12y 8m

Step-by-step explanation:

The amount of principal P at compound monthly at interest rate r per year is given by ...

A = P(1 +r/12)^(12t) . . . . after t years

Here, we want to find t, so ...

A/P = (1 +r/12)^(12t)

log(A/P) = (12t)·log(1 +r/12)

t = log(A/P)/(12·log(1 +r/12))

Filling in the given values, we find t to be ...

t = log(8000/4000)/(12·log(1 +0.055/12)) ≈ 12.6315 ≈ 12 years 7.6 months

It will take about 12 years 8 months to double the money.

8 0

3 years ago

Someone do this got me rq

skelet666 [1.2K]

Answer:

The last listed functional expression:

$\left \{ {x+1\,\,\,\,{x\geq 2} \atop {x+2 \,\,\,\,x$

Step-by-step explanation:

It is important to notice that the two linear expressions that render such graph are parallel lines (same slope), and that the one valid for the left part of the domain, crosses the y-axis at the point (0,2), that is y = 2 when x = 0. On the other hand, if you prolong the line that describes the right hand side of the domain, that line will cross the y axis at a lower position than the previous one (0,1), that is y=1 when x = 0. This info gives us what the y-intercepts of the equations should be (the constant number that adds to the term in x in the equations: in the left section of the graph, the equation should have "x+2", while for the right section of the graph, the equation should have x+1.

It is also important to understand that the "solid" dot that is located in the region where the domain changes, (x=2) belongs to the domain on the right hand side of the graph, So, we are looking for a function definition that contains $x+1$ for the function, for the domain: $x\geq 2$ .

Such definition is the one given last (bottom right) in your answer options.

$\left \{ {x+1\,\,\,\,{x\geq 2} \atop {x+2 \,\,\,\,x$

7 0

3 years ago

Which statement is true of z11.7?

Alexxx [7]

Answer

z11.7 is between 1 and 2 standard deviations of the mean.

Step-by-step explanation:

7 0

2 years ago