1. -a^2+7x^2+16
2. 4z^3+5z^2+z
3. p+4
Poster standard dimension: 8.5 inches by 11 inches
Both length and width of the poster may vary 1/20%
∴ length and width may vary 1/20 % = 0.05% = 0.0005
∵ Area = Width * Length
∴ Area = 8.5 * 11 = 93.5 in²
Smallest acceptable area for one poster:
Width: 8.5 * (1 - 0.0005) = 8.49575 in.
Length: 11 * (1 - 0.0005) = 10.9945 in.
∴ The smallest area = 8.49575 * 10.9945 = 93.4065 ≈ 93.407 in².
Answer:your answer to this prob,problem, is c) $108.75
Step-by-step explanation:
Answer:
9.10806916427
Step-by-step explanation:
Answer:
$25.98
Step-by-step explanation:
8.25% of 24 = 0.0825 × 24 = 1.98
1.98 + 24 = 25.98
