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3 years ago

PLEASE HELP ASAP‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎

Mathematics

1 answer:

Elden [556K]3 years ago

7 0

I think 75 Percent is your answer Please let me know if you get this right

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The table shows transactions in a checking account

Yuki888 [10]

Answer:

i) number of transactions for the month of January = 4

number of transactions for the month of February = 4

number of transactions for the month of March = 4

number of transactions for the month of April = 4

ii) Mean of four months = -495.7 /4 = -123.93

Step-by-step explanation:

i) number of transactions for the month of January = 4

number of transactions for the month of February = 4

number of transactions for the month of March = 4

number of transactions for the month of April = 4

ii) January February March April

-38.50 250.00 -14.00 -86.80

126.30 -135.20 99.00 -570.00

429.40 35.50 -82.70 100.00

-265.00 -62.30 -1.50 -280.10

Total 252.20 88.20 0.80 -836.9

Total of four months = 252.2 + 88.20 + 0.80 - 836.9 = -495.7

Mean of four months = -495.7 /4 = -123.93

6 0

3 years ago

Find the value of n that satisfies 2(n+1)! + 6n! = 3(n+1), where $n! = n\cdot (n-1)\cdot (n-2) \cdots 2\cdot 1$.

Murrr4er [49]

Answer:

$n = 5$

Step-by-step explanation:

Given

$2(n+1)! + 6n! = 3(n+1)!$

Required

Find n

Simplify (n + 1)!

$2(n+1)*n! + 6n! = 3(n+1)*n!$

Factorize

$n![2(n+1) + 6] = 3(n+1)*n!$

Divide both sides by n!

$2(n+1) + 6 = 3(n+1)$

Open brackets

$2n + 2 + 6 = 3n + 3$

$2n + 8 = 3n + 3$

Collect like terms

$2n - 3n = 3 -8$

$-n =-5$

Multiply both sides by -1

$n = 5$

7 0

3 years ago

137x8 multiply with expanded form please help 10 ponte for your help please help!

Step2247 [10]

Answer: maybe 20

Step-by-step explanation:

or find it out yourself

3 0

3 years ago

The steps to derive the quadratic formula are shown below:

alukav5142 [94]

Answer:

(c) x plus b over 2 times a equals plus or minus the square root of the quantity b squared minus 4 times a times c all over the square root of 4 times a squared

Step-by-step explanation:

The next step is to take the square root of both sides of the equation. It can help to show the intermediate steps.

<h3>Result so far</h3>

The last step shown in the derivation so far is ...

$x^2+\dfrac{b}{a}x+\dfrac{b^2}{4a^2}=-\dfrac{4ac}{4a^2}+\dfrac{b^2}{4a^2}$

The left side of the above expression can be written as a square, and the right side can be written over one denominator. Then the square root is taken as the next step.

$\left(x+\dfrac{b}{2a}\right)^2=\dfrac{b^2-4ac}{4a^2}\\\\\sqrt{\left(x+\dfrac{b}{2a}\right)^2}=\sqrt{\dfrac{b^2-4ac}{4a^2}}\\\\\boxed{x+\dfrac{b}{2a}=\pm\dfrac{\sqrt{b^2-4ac}}{\sqrt{4a^2}}}\qquad\text{"next step"}$

7 0

2 years ago

Read 2 more answers

How do I solve these?

Mnenie [13.5K]

6x+4=4x-2 subtract four x to get 2x+4=-2 and subtract 4 and get -6 and divide it by two to get -3

4 0

3 years ago