Answer with Step-by-step explanation:
We are given that two events A and B are mutually exclusive.
![A\cap B=\phi](https://tex.z-dn.net/?f=A%5Ccap%20B%3D%5Cphi)
![P(A\cap B)=0](https://tex.z-dn.net/?f=P%28A%5Ccap%20B%29%3D0)
![P(A)\neq 0](https://tex.z-dn.net/?f=P%28A%29%5Cneq%200)
![P(B)\neq 0](https://tex.z-dn.net/?f=P%28B%29%5Cneq%200)
a.For mutually exclusive events,
![P(A/B)=\frac{P(A\cap B)}{P(B)}=\frac{0}{P(A)}=0](https://tex.z-dn.net/?f=P%28A%2FB%29%3D%5Cfrac%7BP%28A%5Ccap%20B%29%7D%7BP%28B%29%7D%3D%5Cfrac%7B0%7D%7BP%28A%29%7D%3D0)
Therefore, event A can not occurred if event B has occurred because two events can not occur together.
Answer:No, by definition mutually exclusive events cannot occur together.
b.When two events are independent
Then , ![P(A\cap B)=P(A)\cdot P(B)](https://tex.z-dn.net/?f=P%28A%5Ccap%20B%29%3DP%28A%29%5Ccdot%20P%28B%29)
![P(A/B)=\frac{P(A)\cdot P(B)}{P(B)}=P(A)](https://tex.z-dn.net/?f=P%28A%2FB%29%3D%5Cfrac%7BP%28A%29%5Ccdot%20P%28B%29%7D%7BP%28B%29%7D%3DP%28A%29)
If two events are mutually exclusive then
![P(A\cap B)=0](https://tex.z-dn.net/?f=P%28A%5Ccap%20B%29%3D0)
Then , ![P(A/B)=0](https://tex.z-dn.net/?f=P%28A%2FB%29%3D0)
Therefore, ![P(A/B)\neq P(A)](https://tex.z-dn.net/?f=P%28A%2FB%29%5Cneq%20P%28A%29)
Hence, we can concluded that events A and B are not independent if they are mutually exclusive.
Answer:Yes, ![P(A/B)\neq P(A)](https://tex.z-dn.net/?f=P%28A%2FB%29%5Cneq%20P%28A%29)
Answer:
A
Step-by-step explanation:
empirical formulas are the simplest form of notation so they provide the lowest whole number ratio between the elements in a compound
Answer: 40.15
Step-by-step explanation: 40.15 IS LESS THEN 48.60
Answer:
x = 8
Step-by-step explanation:
30x = (60)(40)
30x = 240 Multiply 60 and 40
x = 8 Divide 30 from both sides